Hydrogen and Helium cannot bond together. Put aside the inertness of helium (or all noble gases), bond formation is only favored when the final state of the two elements is more stable than their initial state. ... Helium compounds has some predictions though none of them contain only those two elements.
The atomic mass of the magnesium is : 24.31⋅g.
<h3>What is isotopes?</h3>
Isotopes are members of a family of elements that all have the same number of protons and different numbers of neutrons. The number of protons in the nucleus determines the atomic number of an element on the periodic table.
Magnesium has three natural isotopes: ²⁴Mg, ²⁵Mg, and ²⁶Mg.
<h3>What is atomic mass ?</h3>
Atomic mass is the mass of an atom. The SI unit of mass is the kilogram, while atomic mass is often expressed in the non-SI unit dalton (synonymous with uniform atomic mass unit). 1 Da is defined as 1/12 the mass of a free carbon-12 atom at rest in the ground state.
Calculation :
The atomic mass is the weighted average of the individual isotopic masses:
(23.99×78.99%+24.99×10.00%+25.98×11.01%)⋅g=24.31⋅g
To know more atomic mass please click here : brainly.com/question/338808
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Answer:
Explanation:
The number of moles of solute is equal to product of the molar concentration (molarity) and the volume (in liters) of solution.
Since the volumes and the molar concentrations of the<em> NaOH </em>and <em>HCl </em>solutions mixed are equal, each one of them contributes the same number of moles of solute.
Since every mol of NaOH produces one mol of OH⁻ ions and every mol of HCl produces one mol of H⁺ ion, the number of moles of OH ⁻ and H⁺ in solution are equal.
Thus, OH⁻ and H⁺ ions will be neutralized by the reaction:
- OH⁻ (aq) + H⁺ (aq) ⇄ H₂O (l)
Which is strongly shifted to the right and has <em>neutral pH</em>.
Hence, you conclude that the approximate <em>pH of the solution is neutral.</em>
Answer:
The upper and lower limits for the room-temperature thermal conductivity of a magnesium oxide material having a volume fraction of 0.10 of pores that are filled with still air are
Ku = 38.252 W/mK
K lower = 0.199 W/mK
Explanation:
As we know
Ku = Vp * Kair + Vmagnesium * K metal
Ku = 0.10 *0.02 + (1-0.25) * 51
Ku = 38.252 W/mK
The lower limit
K lower = Kmetal* Kair/( Vp * Kmetal + Vmetal * K air)
K lower = (0.02*51)/(0.10*51 + 0.90 * 0.02)
K lower = 0.199 W/mK
F = ma = (kg)(m/s2) = kg ´ m/s2 N
hope this helps :D
