<span>just find the percent mass of oxygen in sucrose again. and then multiply that by 50.00.</span>
I’m not sure what the answer is but I hope someone can help you
Answer: There are 
molecules in 63.00 g of 
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 
of particles.
To calculate the moles, we use the equation:
1 mole of contains = molecules
Thus 3.5 moles of contains = 
molecules.
There are molecules in 63.00 g of
Answer: 97.2223 ml
Explanation:
The rule that we will use to solve this problem is:
M2*V1 = M2*V2 where:
M1 is the initial concentration = 3.5 m
V1 is the initial volume = 0.25 l = 250 ml
M2 is the final concentration = 9 m
V2 is the final volume that we need to find
Substitute with the givens in the above equation to get V2 as follows:
3.5*250 = 9*V2
V2 = <em><u>97.2223 ml</u></em>
Answer:
The answer to your question is 126.1°C
Explanation:
Boiling point Difference of boiling points
C₃H₈ - 42.1°C
C₄H₁₀ - 0.5°C 41.6 °C
C₅H₁₂ 36.1°C 36.6°C 41.6 - 36.6 = 5°C
C₆H₁₄ 68.7°C 32.6°C 36.6 - 32.6 =4°C
C₇H₁₆ 98.4°C 29.7°C 32.6 - 29.7 = 2.9°C
We can observe on the table that the difference of boiling points diminishes 1°C when the hydrocarbon has one more carbon, then the difference of temperature between the hydrocarbon of 8 carbons and the hydrocarbon of 7 carbons must be 2°C.
So, this difference is 29.7°C - 2°C = 27.7°C.
And the boiling point of octane is approximately 98.4 + 27.7°C = 126.1°C
