Suppose that a formic acid (hcooh) solution has a ph of 3.15. which of these substances would increase the ph of the solution?

Chemistry

1 answer:

grin007 [14]2 years ago

6 0

NaCHO would increase the ph of the solution

NaBr and KCl are neutral substances that cannot change the pH of the formic acid solution.

Since HCl is a potent acid, adding more of it will cause the pH of the solution to decrease even more. Regarding NaCHO, it stands for sodium citrate, which is a weak base. NaCHO can thereby increase the pH of the formic acid solution.

There are many different ways to define acids and bases. According to the bronsted-Lowry definition, a base is a proton acceptor, whereas an acid is a proton giver. According to Lewis, an acid is an electron pair acceptor, whereas a base is an electron pair giver.

Learn more about Acid and base here:

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Given the following unbalanced equation:

Lorico [155]

<h3>Answer:</h3>

8.01 mol MgO

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Moles
Compounds

<u>Stoichiometry</u>

Using Dimensional Analysis
Analyzing Reactions RxN

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Unbalanced] Mg + O₂ → MgO

[RxN - Balanced] 2Mg + O₂ → 2MgO

[Given] 8.01 moles Mg

[Solve] moles MgO

<u>Step 2: Identify Conversions</u>

[RxN] 2 mol Mg → 2 mol MgO

<u>Step 3: Stoich</u>

[DA] Set up: $\displaystyle 8.01 \ mol \ Mg(\frac{2 \ mol \ MgO}{2 \ mol \ Mg})$
[DA] Multiply/Divide [Cancel out units]: $\displaystyle 8.01 \ mol \ MgO$