The question is incomplete, here is the complete question:
Consider the reaction 
Initially, ![[NH_3(g)]=[O_2(g)]](https://tex.z-dn.net/?f=%5BNH_3%28g%29%5D%3D%5BO_2%28g%29%5D)
= 3.60 M; at equilibrium ![[N_2O_4(g)]=0.60M](https://tex.z-dn.net/?f=%5BN_2O_4%28g%29%5D%3D0.60M)
. Calculate the equilibrium concentration for 
<u>Answer:</u> The equilibrium concentration of ammonia is 2.8 M
<u>Explanation:</u>
We are given:
Initial concentration of ![[NH_3(g)]](https://tex.z-dn.net/?f=%5BNH_3%28g%29%5D)
= 3.60 M
Initial concentration of ![[O_2(g)]](https://tex.z-dn.net/?f=%5BO_2%28g%29%5D)
= 3.60 M
For the given chemical equation:
Initial: 3.60 3.60
At eqllm: 3.60-4x 3.60-7x 2x 6x
We are given:
Equilibrium concentration of ![[N_2O_4(g)]](https://tex.z-dn.net/?f=%5BN_2O_4%28g%29%5D)
= 0.60 M
Evaluating the value of 'x'
So, equilibrium concentration of 
Hence, the equilibrium concentration of ammonia is 2.8 M
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Answer:
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the only process out of the four that does not happen in both animals implants would be photosynthesis. photosynthesis is when the cell takes the energy from the Sun's UV rays and turns into a form of energy that it can use
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