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agasfer [191]
3 years ago
10

Write in the chart which molecule is the acid,base, conjugate base,conjugate acid from the equation and watching the H+ movement

Chemistry
1 answer:
Brrunno [24]3 years ago
5 0

Answer:

When H2O acts as a base, it gains one H, which forms its conjugate acid, H30. ... Write the formula for the conjugate base for each of the following acids: a. ... H3PO4(aq) + H2O(l) 7 H2PO4 (aq) + H3O+(aq) ... CO32-(aq) + H2O(1) 2 HCO3 (aq) + OH(aq) ... balanced equation for the reaction of the ammonium ion with water.

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The equation below shows lithium reacting with nitrogen to produce lithium nitride. 6Li + N2 mc007-1.jpg 2Li3N If 12 mol of lith
andrew11 [14]

Answer is: 4.0 mol of lithium nitride would be produced.

Balanced chemical reaction: 6Li + N₂ → 2Li₃N.

n(Li) = 12 mol; amount of substance.

From chemical reaction: n(Li) : n(Li₃N) = 6 : 2 (3 : 1).

n(Li₃N) = n(Li) ÷ 3.

n(Li₃N) = 12 mol ÷ 3.

n(Li₃N) = 4 mol; amount of lithium nitride.

4 0
3 years ago
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PLS HELP!!! ASAP
mina [271]

Answer: The answer is Fossil A is younger than the index fossil.

Explanation: Because it’s the newest layer

7 0
4 years ago
Is this true Bc I’m not sure
Andrew [12]

Answer:

????? questions there no question

4 0
3 years ago
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Why carbon nanotubes are so strong? Quick please urgent
Goryan [66]

Answer: Carbon nanotubes, especially multi walled carbon nanotubes, are so strong because they are a single chain of unbroken covalent carbon-carbon bonds.

Explanation:

7 0
4 years ago
how many grams of CsXeF7 can be produced from the reaction of 15.2 grams of CsF and 260 grams of XeF6?
Sveta_85 [38]

Answer:

39.72 g

Explanation:

Given data:

Mass of CsF = 15.2 g

Mass of XeF₆ = 260 g

Mass of Cs[XeF₇] = ?

Solution:

Chemical reaction:

CsF + XeF₆   →  Cs[XeF₇]

Number of moles of CsF:

Number of moles = mass/ molar mass

Number of moles = 15.2 g/151.9 g/mol

Number of moles = 0.1 mol

Number of moles of XeF₆ :

Number of moles = mass/ molar mass

Number of moles = 260 g/245.28 g/mol

Number of moles = 1.06 mol

Now we will compare the moles of Cs[XeF₇] with both reactants.

                            CsF               :            Cs[XeF₇]

                               1                 :                 1

                             0.1                :              0.1

                             XeF₆            :           Cs[XeF₇]

                                 1               :               1

                                1.06           ;              1.06

Number of moles of Cs[XeF₇] produce by  CsF are less so it will limiting reactant and limit the yield of Cs[XeF₇].

Mass of Cs[XeF₇]:

Mass = number of moles × molar mass

Mass = 0.1 mol × 397.2 g/mol

Mass = 39.72 g

4 0
3 years ago
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