A functional group introduces heteroatoms into a carbon chain to increase

An atorn has 9 electrons and 9 protons at the start. If it loses 2 electrons, the net charge on the atom will be. If the atom in

LUCKY_DIMON [66]

Answer:

If it loses 2 electrons, the net charge on the atom will be 2+

If the atom instead gains 4 electrons, the net charge will be 4-

Explanation:

It is based on adding and subtracting charges. Protons are +1 and electrons are -1

If the atom has 9 protons and 9 electrons, the net charge is +9 + (-9) = 0. The +9 is the 9 protons and the -9 is from the 9 electrons.

If two electrons are taken away, there would be 9-2 or 7 electrons with 9 protons. The net charge would then be +9 + (-7) = +2. +9 comes from the 9 electrons and -7 is from the 7 electrons.

So, if two electrons are taken away, the net charge is +2.

Similarly, if the atom gains 4 electrons, there will be 9+4 or 12 electrons and 9 protons. The net charge would then be +9 + (-12) = -4. +9 comes from the 9 protons and -12 comes from the 12 electrons.

So, if 4 electrons are added, the net charge is -4.

3 0

3 years ago

During a synthesis reaction, 2.4 grams of magnesium reacted with 8.0 grams of oxygen. What is the maximum amount of magnesium ox

natali 33 [55]

Answer: The maximum amount of magnesium oxide produced during the reaction can be, 3.9 grams.

Explanation : Given,

Mass of $Mg$ = 2.4 g

Mass of $O_2$ = 8.0 g

Molar mass of $Mg$ = 24.3 g/mol

Molar mass of $O_2$ = 31.9 g/mol

First we have to calculate the moles of $Mg$ and $O_2$ .

$\text{Moles of }Mg=\frac{\text{Given mass }Mg}{\text{Molar mass }Mg}$

$\text{Moles of }Mg=\frac{2.4g}{24.3g/mol}=0.099mol$

and,

$\text{Moles of }O_2=\frac{\text{Given mass }O_2}{\text{Molar mass }O_2}$

$\text{Moles of }O_2=\frac{8.0g}{31.9g/mol}=0.25mol$

Now we have to calculate the limiting and excess reagent.

The balanced chemical equation is:

$2Mg+O_2\rightarrow 2MgO$

From the balanced reaction we conclude that

As, 2 mole of $Mg$ react with 1 mole of $O_2$

So, 0.099 moles of $Mg$ react with $\frac{0.099}{2}=0.049$ moles of $O_2$

From this we conclude that, $O_2$ is an excess reagent because the given moles are greater than the required moles and $Mg$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $MgO$

From the reaction, we conclude that

As, 2 mole of $Mg$ react to give 2 mole of $MgO$

So, 0.099 mole of $Mg$ react to give 0.099 mole of $MgO$

Now we have to calculate the mass of $MgO$

$\text{ Mass of }MgO=\text{ Moles of }MgO\times \text{ Molar mass of }MgO$

Molar mass of $MgO$ = 40.3 g/mole

$\text{ Mass of }MgO=(0.099moles)\times (40.3g/mole)=3.9g$

Therefore, the maximum amount of magnesium oxide produced during the reaction can be, 3.9 grams.

7 0

3 years ago

We can change a gas to liquid by_________ the temperature and_________

Tpy6a [65]

Decreasing, Removing

6 0

3 years ago

Which change would most likely increase the resistance in the circuit ?

yaroslaw [1]

Answer:

I think it would be C but don't quote me on it

Explanation:

It adds another obstacle for the current to go through

4 0

2 years ago

Why can a magnet separate iron and sulphur in a mixture but not a compound?

KengaRu [80]

Answer:

A compound is different from elements in that it is made from the chemical union of two or more elements. ... Mixtures are different from compounds in that they are easily separated. A magnet could be used to separate the iron from the sulfur, because iron is attracted to magnets, while sulfur is not.

Explanation:

6 0

3 years ago