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Paladinen [302]
2 years ago
12

What type of intermolecular forces are expected between 3-bromopyridine molecules?

Chemistry
1 answer:
ahrayia [7]2 years ago
7 0

Type of intermolecular forces are expected between 3-bromopyridine molecules dipole induced dipole force.

Intermolecular pressure is the pressure among molecules it includes the forces of appeal and repulsion. however the intermolecular forces are weaker than intramolecular pressure, has London dispersion pressure.

Dipole precipitated Dipole Forces A dipole-brought on dipole enchantment is a weak enchantment that results while a polar molecule induces a dipole in an atom or in a non polar molecule by traumatic the arrangement of electrons inside the non polar species.

It is a dipole as the hydrogens have a partial superb fee and the oxygen has a partial negative charge. An precipitated dipole is the end result of  molecules interacting and causing one of the molecules electrons to have this distorted rate.

Learn more about  induced dipole here:- brainly.com/question/22973877

#SPJ4

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Whats the difference between an atom and an ion?
Tpy6a [65]

An atom is the fundamental unit of matter and it contains an equal number of protons and electrons in its nucleus which makes it electrically neutral. An ion however, is an atom containing an unequal number of protons and electrons which means it will either carry a net positive charge or negative charge depending on whether there are more electrons or protons.

7 0
3 years ago
Read 2 more answers
Now consider the reaction when 45.0 g NaOH have been added. What amount of NaOH is this, and what amount of FeCl3 can be consume
gayaneshka [121]

The correct answer is that 1.125 mol of NaOH is available, and 60.75 g of FeCl₃ can be consumed.

The mass of NaOH is 45 g

The molar mass of NaOH = 40 g/mol

The moles of NaOH = mass / molar mass

= 45 / 40

= 1.125

Thus, 1.125 mol NaOH is available

3 NaOH + FeCl₃ ⇒ Fe (OH)₃ + 3NaCl

3 mol of NaOH react with 1 mol of FeCl₃

1.125 moles of NaOH will react with x moles of FeCl₃

x = 1.125 / 3

x = 0.375 mol

0.375 mol FeCl₃ can take part in reaction

The molar mass of FeCl₃ is 162 g/mol

The mass of FeCl₃ = moles × mass

= 0.375 × 162

= 60.75 g

Thus, the amount of FeCl₃, which can be consumed is 60.75 g

6 0
3 years ago
A 75.0-milliliter lightbulb is filled with neon. There are 7.16 × 10-4 moles of gas in it, and the absolute pressure is 116.8 ki
Alexeev081 [22]

n = number of mole of sample of helium gas = 7.16 x 10⁻⁴ moles

T = temperature of the gas = temperature of the bulb ?

V = Volume of helium gas = 75 mL = 7.5 x 10⁻⁵ m³

P = pressure of the helium gas = 116.8 kPa = 116.8 x 10³ Pa      (1 k = 1000)

Using the equation

P V = n R T

inserting the values

(116.8 x 10³) (7.5 x 10⁻⁵) = (7.16 x 10⁻⁴) (8.314) T

T = 1471.6 C


8 0
3 years ago
Read 2 more answers
"Construct a multistep synthetic route from ethylbenzene to (2-bromoethyl)benzene by dragging the appropriate items into the bin
umka2103 [35]

Answer:

The best reagents that are used for the conversion of ethylbenzene to (2-bromoethyl)benzene is shown in the first diagram attached.

Explanation:

Concepts and reason

The concept used to solve this problem is by using the given reagents, possible products will be formed in each step and then label it exactly in the given boxes in order to form the exact product.

Here, the starting reactant is ethyl benzene and the final product is (2-bromoethyl)benzene.

Fundamentals

Bromine molecule is used for bromination of alkene. Trans addition takes place.

Addition of HBr to the double bond forms an alkyl bromide.

Potassium tertiary butoxide is a sterically hindered base.

Bromination of alkane in the presence of sunlight gives radical substitution.

NBS (N-bromosuccinimide) is used for the allylic bromination.

The reaction is as shown in the second attachment(pictures 2,3 and 4).

8 0
3 years ago
Determine the empirical formula of H 3.66%; P 37.8%; O 58.5%
Phoenix [80]
We have atomic masses of: (omit units)
O=16
H=1
P=39
So:
O=58,5/16=3,65/1,21=3,01≈3
H=3,66/1=3,66/1.21=3,02≈3
P=37,8/31=1,21/1,21=1
So the empiric formula is:
H₃PO₃
3 0
3 years ago
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