An atom is the fundamental unit of matter and it contains an equal number of protons and electrons in its nucleus which makes it electrically neutral. An ion however, is an atom containing an unequal number of protons and electrons which means it will either carry a net positive charge or negative charge depending on whether there are more electrons or protons.
The correct answer is that 1.125 mol of NaOH is available, and 60.75 g of FeCl₃ can be consumed.
The mass of NaOH is 45 g
The molar mass of NaOH = 40 g/mol
The moles of NaOH = mass / molar mass
= 45 / 40
= 1.125
Thus, 1.125 mol NaOH is available
3 NaOH + FeCl₃ ⇒ Fe (OH)₃ + 3NaCl
3 mol of NaOH react with 1 mol of FeCl₃
1.125 moles of NaOH will react with x moles of FeCl₃
x = 1.125 / 3
x = 0.375 mol
0.375 mol FeCl₃ can take part in reaction
The molar mass of FeCl₃ is 162 g/mol
The mass of FeCl₃ = moles × mass
= 0.375 × 162
= 60.75 g
Thus, the amount of FeCl₃, which can be consumed is 60.75 g
n = number of mole of sample of helium gas = 7.16 x 10⁻⁴ moles
T = temperature of the gas = temperature of the bulb ?
V = Volume of helium gas = 75 mL = 7.5 x 10⁻⁵ m³
P = pressure of the helium gas = 116.8 kPa = 116.8 x 10³ Pa (1 k = 1000)
Using the equation
P V = n R T
inserting the values
(116.8 x 10³) (7.5 x 10⁻⁵) = (7.16 x 10⁻⁴) (8.314) T
T = 1471.6 C
Answer:
The best reagents that are used for the conversion of ethylbenzene to (2-bromoethyl)benzene is shown in the first diagram attached.
Explanation:
Concepts and reason
The concept used to solve this problem is by using the given reagents, possible products will be formed in each step and then label it exactly in the given boxes in order to form the exact product.
Here, the starting reactant is ethyl benzene and the final product is (2-bromoethyl)benzene.
Fundamentals
Bromine molecule is used for bromination of alkene. Trans addition takes place.
Addition of HBr to the double bond forms an alkyl bromide.
Potassium tertiary butoxide is a sterically hindered base.
Bromination of alkane in the presence of sunlight gives radical substitution.
NBS (N-bromosuccinimide) is used for the allylic bromination.
The reaction is as shown in the second attachment(pictures 2,3 and 4).
We have atomic masses of: (omit units)
O=16
H=1
P=39
So:
O=58,5/16=3,65/1,21=3,01≈3
H=3,66/1=3,66/1.21=3,02≈3
P=37,8/31=1,21/1,21=1
So the empiric formula is:
H₃PO₃