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11Alexandr11 [23.1K]
4 years ago
11

Which compound will form from the bonding of CA and N ca3N2, Ca2N3, Ca2N2, caN​

Chemistry
1 answer:
Paladinen [302]4 years ago
4 0

Answer:

Ca3N2

Explanation:

Ca+2

N-3

Criss cross the charges to get Ca3N2

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The equation shows the reaction between magnesium and chlorine to produce magnesium chloride.
Anestetic [448]

Answer: Mg is a cation and Cl is an anion

Explanation: In more detail, if you look at the periodic table, the group number (or columns) of the elements, describe how many valence electrons, or how many electrons the element has available to have a complete an electron shell. Magnesium being in group 2, it has one 2 electrons that will be "donated" to an anion that it bonds with. However, Chlorine being in group 17, (look at the single digit number for double digit groups), it has 7 valence electrons. Knowing that a full electron shell is usually 8 electrons, it needs only one. Since Magnesium has 2 valence electrons to give away, two atoms of Chlorine gas will then bind to the Magnesium, where the 2 Chlorine atoms will take the electrons to fill their shells. Magnesium Chloride, in terms of charges when in ions, [Mg]2+ and 2 [Cl]-1

7 0
3 years ago
A sample of a compound consisting only of copper and sulfur contains 88.39g of the metal and 44.61g of non-metal. How many grams
Lorico [155]
<span>(88.39 / (88.39 + 44.61) ) x (5264000) = answer for copper grams 

(44.61 / (88.39 + 44.61)) x (5264000) = answer for sulfur grams 

Sulfur is a non-metal used to make paper, number 16 on periodic table.</span><span>

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6 0
4 years ago
The number of molecules in one mole of lithium acetate are...
Citrus2011 [14]

Answer:

  6.0221409e+23

Explanation:

The number of molecules in a mole of any substance is Avogadro's number, 6.0221409e+23.

8 0
3 years ago
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Hey there!

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3 years ago
One mole of ar initially at 305 k undergoes an adiabatic expansion against a pressure pexternal = 0 from a volume of 8.5 l to a
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An adiabatic process is when the system is insulated that no heat is released to the surroundings. For this type of process, we have a derived formula written below:

(T₂/T₁)^C = (V₁/V₂)
where C = Cv/nR

From the complete problem shown in the attached picture, Cv = (3/2)R. Thus,
C= (3/2)/1 mol = 3/2

(T₂/305 K)^(3/2) = (8.5 L/82 L)
Solving for T₂,
<em>T₂ = 67.3 K</em>

3 0
3 years ago
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