Answer:
The center of the atom contains the nucleus so yes
Explanation:
Answer:
Group 1 and 2 elements
Explanation:
Nitrogen, a non-metal will form ionic bonds with most group 1 and group 2 metals on the periodic table.
How does ionic bonds form?
- They are bonds formed between a highly electronegative specie and one with very low electronegativity.
- As such, ionic bonds forms between metals and non-metals
- In this bond type, the metal due to its electropositive nature will transfer electrons to the non-metals for it to gain.
- The non-metals becomes negatively charged as the metal is positively charged.
- The electrostatic attraction between the two specie leads to the formation of ionic bonds.
Most metals in group 1 and 2 fits in this description. Some of them are calcium, magnesium, lithium, Barium e.t.c.
It mostly favors group 2 metals.
Answer:
2H2(g]+O2(g]→2H2O(l]]. Notice that the reaction requires 2 moles of hydrogen gas and 1
Explanation:
Answer: The molarity of this solution is 0.159 M.
Explanation:
Given: Mass of solute = 16.3 g
Volume = 1.75 L
Number of moles is defined as the mass of substance divided by its molar mass.
Hence, moles of NaCl (molar mass = 58.44 g/mol) ar calculated as follows.

Molarity is the number of moles of a substance present in a liter of solution.
So, molarity of the given solution is calculated as follows.

Thus, we can conclude that the molarity of this solution is 0.159 M.
<h3>
Answer:</h3>
10.6 mol NO
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Stoichiometry</u>
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[RxN - Balanced] 4NH₃ + 5O₂ → 4NO + 6H₂O
[Given] 13.2 mol O₂
<u>Step 2: Identify Conversions</u>
[RxN] 5 mol O₂ → 4 mol NO
<u>Step 3: Stoich</u>
- [DA] Set up:

- [DA] Multiply/Divide [Cancel out units]:

<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
10.56 mol NO ≈ 10.6 mol NO