<u>Answer:</u> The mass of the final mixture is 350 grams and composition of methanol in the final mixture is 52.9 %
<u>Explanation:</u>
<u>In first mixture:</u>
Mass of first mixture taken, = 200 g
Percentage of methanol, = 40 % = 0.4
Percentage of water, = (100 - 40)% = 60% = 0.6
<u>In second mixture:</u>
Mass of second mixture, = 150 g
Percentage of methanol, = 70 % = 0.7
Percentage of water, = (100 - 70)% = 30% = 0.3
Let us consider that no chemical reaction is taking place while mixing the solutions.
Calculating the mass of methanol and water in the final mixture:
Putting values in above equation, we get:
Putting values in above equation, we get:
Total mass of the final mixture =
To calculate the percentage composition of methanol in final mixture, we use the equation:
Mass of final mixture = 350 g
Mass of methanol = 185 g
Putting values in above equation, we get:
Hence, the mass of the final mixture is 350 grams and composition of methanol in the final mixture is 52.9 %