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Aleonysh [2.5K]
3 years ago
12

3. Write down the total thermal resistance for a double-pipe heat exchanger. Show how to convert from total resistance to an ove

rall heat-transfer coefficient. Explain how flow regime may affect overall heat transfer rate.

Engineering
2 answers:
wlad13 [49]3 years ago
8 0

Answer: please check image for detailed calculation and explanation.

At the boundary between the pipes, there is discontinuity due to different regime; this gap can insulate heat flow causing a fluctuation in heat flow from the inner pipe to the outer pipe.

Nutka1998 [239]3 years ago
8 0

Answer:

\frac{1}{UA} =\frac{1}{A_{0}h_{0}  } +\frac{Rf_{0} }{A_{0} } +\frac{1}{2k\pi L} ln(\frac{di,0}{di,i} )+\frac{Rf_{i} }{A_{i} }

Explanation:

Global heat transfer determines the heat that is transferred from the inner tube to the outer tube. In the double tube heat exchanger, this global heat transfer coefficient is equal to:

\frac{1}{UA} =\frac{1}{A_{0}h_{0}  } +\frac{Rf_{0} }{A_{0} } +\frac{1}{2k\pi L} ln(\frac{di,0}{di,i} )+\frac{Rf_{i} }{A_{i} }

where subscript i refers to the inner surface and subscript 0 refers to the outer surface

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At an axial load of 22 kN, a 15-mm-thick × 40-mm-wide polyimide polymer bar elongates 4.1 mm while the bar width contracts 0.15
Alenkasestr [34]

Answer:

The Poisson's Ratio of the bar is 0.247

Explanation:

The Poisson's ratio is got by using the formula

Lateral strain / longitudinal strain

Lateral strain = elongation / original width (since we are given the change in width as a result of compession)

Lateral strain = 0.15mm / 40 mm =0.00375

Please note that strain is a dimensionless quantity, hence it has no unit.

The Longitudinal strain is the ratio of the elongation to the original length in the longitudinal direction.

Longitudinal strain = 4.1 mm / 270 mm = 0.015185

Hence, the Poisson's ratio of the bar is 0.00375/0.015185 = 0.247

The Poisson's Ratio of the bar is 0.247

Please note also that this quantity also does not have a dimension

3 0
3 years ago
Which of the following explains the main reason to cut a piece of wood on the outside of the measurement mark?
maks197457 [2]
I think it’s D ?? I’m not completely sure tho
4 0
3 years ago
After replacing a vacuum booster, the brakes lock up on a road test. Technician A says there is air trapped inside the brake lin
vitfil [10]

Answer:

Technician B

Explanation:

The brakes can lockup due to the following reasons

1) Overheating break systems

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5 0
3 years ago
Cavitation usually occurs because:
IgorLugansk [536]

Answer:

B) the liquid accelerated to high velocities.

<em>I</em><em> </em><em>hope</em><em> </em><em>this helps</em><em> </em>

3 0
3 years ago
The water in a 25-m-deep reservoir is kept inside by a 140-m-wide wall whose cross section is an equilateral triangle as shown i
koban [17]

Answer:  (a) 9.00 Mega Newtons or 9.00 * 10^6 N

               (b)  17.1 m

Explanation:  The length of wall under the surface can be given by

                                            b=25m/sin(60)\\=28.867

The average pressure on the surface of the wall is the pressure at the centeroid of the equilateral triangular block which can be then be calculated by multiplying it with the Plate Area which will provide us with the Resultant force.

F(resultant) = Pavg ( A) = (Patm +  \rho g h c)*A \\= [100000 N/m^2 + (1000 kg/m^3 * 9.81 m/s^2 * 25m/2)]* (140*25m/sin60)\\= 8.997*10^8 N \\= 9.0*10^8 N

Noting from the Bernoulli  equation that

Po/\rho g sin60 = 100000/1000 * 9.81* sin(60) = 11.77 m \\ \\

From the second image attached the distance of the pressure center from the free surface of the water along the surface of the wall is given by:

Yp = s+\frac{b}{2} +\frac{b^2}{s+\frac{b}{2}+Po/\rho g sin60}= 0+\frac{28.87}{2} +\frac{28.87^2}{0+\frac{28.87}{2}+100000 /1000 *9.81 sin60} = 17.1 m

Substituting the values gives us the the distance of the surface to be equal to = 17.1 m

7 0
3 years ago
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