Router bits with cutting lips on the ends are for
1 answer:
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Answer:
77.2805 μF
Explanation:
Given data :
V = 2460 V
Q = 191 Kva
<u>Calculate the size of Each capacitor </u>
first step : calculate for the value of Xc
Q = V^2/ Xc
Xc ( capacitive reactance ) = V^2 / Q = 2460^2 / ( 191 * 10^3 ) = 31.683 Ω
Given that 1 / 2πFc = 31.683
∴ C ( size of each capacitor ) = = 77.2805 μF
Answer:
Force per unit plate area is 0.1344
Solution:
As per the question:
The spacing between each wall and the plate, d = 10 mm = 0.01 m
Absolute viscosity of the liquid,
Speed, v = 35 mm/s = 0.035 m/s
Now,
Suppose the drag force that exist between each wall and plate is F and F' respectively:
Net Drag Force = F' + F''
where
= shear stress
A = Cross - sectional Area
Therefore,
Net Drag Force, F =
Also
F =
where
= dynamic coefficient of viscosity
Pressure, P =
Therefore,