Find the value for x

I'll give brainlest <3

AleksandrR [38]

45 maybe bc it’s small

3 0

2 years ago

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Ini apa we jawabannya pelasee

kupik [55]

Answer:

<h3></h3><h2><u>kualitas terjemahannya mungkin tidak bagus. Jadi lihat 2 baris terakhir jika Anda tidak mengerti.</u></h2>

Jadi jumlah derajat tidak masalah. Mereka masih akan menempuh jarak yang sama.

Karena Anda mengatakan bahwa ekspres Marina berjalan pada 40 km / jam dan kami melakukan 2 jam. 40 * 2 = 80 km. Untuk Dumai Anda melakukan hal yang sama, 48 * 2 = 96.

Marina berjalan sejauh 80 km

Dumai berjarak 96 km

8 0

3 years ago

Which of the following in not a method used to determine latitude?

Vesnalui [34]

The correct answer is quadrant.

Quadrant is a method used to determine latitude. Chronometer is used to measure time. Astrolabe is used by navigators and astrologers. Cross-staff or Jacob's staff is used to measure angles. So the correct answer would be quadrant. I hope this helped you.

6 0

3 years ago

Listed below are the numbers of heroic firefighters who lost their lives in the United States each year while fighting forest fi

Marysya12 [62]

Answer:

Step-by-step explanation:

Hello!

Data

Year/Firefighters

2000: 20

2001: 18

2002: 23

2003: 30

2004: 20

2005: 12

2006: 24

2007: 9

2008: 25

2009: 15

2010: 8

2011: 11

2012: 15

2013: 34

<u>Common measures of variation</u>

<u>Variance</u>

S²= $\frac{1}{n-1}[sumX^2-\frac{(sumX)^2}{n} ]$

∑X= 20 + 18 + 23 + 30 + 20 + 12 + 24 + 9 + 25 + 15 + 8 + 11 + 15 + 34

∑X= 264

∑X²= 20² + 18² + 23² + 30² + 20² + 12² + 24² + 9² + 25² + 15² + 8² + 11² + 15² + 34²

∑X²= 5770

n= 14

S²= $\frac{1}{13}[5770-\frac{(264)^2}{14} ]$

S²= 60.90

<u>Standard deviation</u>

The standard deviation is the square root of the variance

S= √S²= √60.90= 7.80

<u>Coefficient of variation</u>

Is a relative standard deviation, it is defined as the division of the standard deviation (S) by the mean (X[bar)]. It has not units and is usually expressed in percentage. It shows the variability in relation to the mean.

C.V.= $\frac{S}{X[bar]}$ *100 = $\frac{7.80}{18.86}$ *100= 41.36%

The mean or average is a measurement of position and gives you an idea of the central value of the distribution of the data.

X[bar]= ∑X/n= 264/14= 18.86

<u>Range</u>

In the interval between the max and min values. It allows you to have an idea of the dispersion of the values.

R= Xmax - Xmin= 34 - 8= 26

Xmax= 34

Xmin= 8

<u>Inter Quartile Range</u>

Is the difference between Quantile 1 (C₁) and Quantile 3 (C₃). It shows the 50% mid values of the sample.

IQR= C₃ - C₁= 23.5 - 11.5 = 12

Quantile 1 (C₁) is the value that leaves 25% of the sample below and 75% of the sample above.

Pos1: n/4= 14/4= 3.5

The first quantile is the number between position 3 and position 4

8, 9, 11, 12, 15, 15, 18, 20, 20, 23, 24, 25, 30, 34

C₁= (11+12)/2= 11.5

Quantile 3 (C₃) is the value that leaves 75% of the sample below and 25% of the sample above.

Pos3: n*3/4= 14*3/4= 10.5

The third Quantile is between position 10 and 11

8, 9, 11, 12, 15, 15, 18, 20, 20, 23, 24, 25, 30, 34

C₃= (23+24)/2= 23.5

The measurements of variation don't allow you to know the origin of the data, that it is from consecutive years.

I hope it helps!

6 0

3 years ago

AHHHHHHHHHHHHHHH SOMEONE ANSWEER THIS PLEEASEEE NEED ANSWER ASP 20 pts!! Please answer!!! I literally don't get this ;c so PLEAS

Blababa [14]

Answer:

$P(A\textrm{ and }B)=\frac{3}{14}$

Step-by-step explanation:

Given:

$P(A)=\frac{4}{7}$

$P(B|A)=\frac{3}{8}$

We know that, conditional probability of B given that A has occurred is given as:

$P(B|A)=\frac{P(A\cap B}{P(A)}$ . Expressing this in terms of $P(A\cap B)$ , we get

$P(A\cap B)=P(B|A)\times P(A)$

Plug in the known values and solve for $P(A\cap B)$ . This gives,

$P(A\cap B)=P(B|A)\times P(A)\\P(A\cap B)=\frac{3}{8}\times \frac{4}{7}\\P(A\cap B)=\frac{12}{56}=\frac{3}{14}$

Therefore, the probability of events A and B occurring is $\frac{3}{14}$ .

6 0

3 years ago

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