Find the value for x

X= b- cd for c please solve and show work

SVETLANKA909090 [29]

Answer:

c=b-x/d hope it helps..............

8 0

2 years ago

In a one-way ANOVA, what is the difference between the among-groups variance MSA and the within-groups variance MSW?

LuckyWell [14K]

Answer:

$MSR=MSA=\frac{SSR}{k-1}$

And $MSE=MSW=\frac{SSE}{N-k}$

The difference is that MSA takes incount the variation between the groups and the grand mean, and the MSW takes in count the variation within groups respect to the mean of each group .

Step-by-step explanation:

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"

If we assume that we have $j$ groups and on each group from $j=1,\dots,j$ we have $n_j$ individuals on each group we can define the following formulas of variation:

$SS_{total}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2$

$SS_{between=Treatment}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2$

$SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2$

And we have this property

$SST=SS_{between}+SS_{within}=6750+8000=14750$

The degrees of freedom for the numerator on this case is given by $df_{num}=k-1$ where k represent the number of groups.

The degrees of freedom for the denominator on this case is given by $df_{den}=df_{between}=N-k$ .

And the total degrees of freedom would be $df=N-1$

We can find the $MSR=MSA=\frac{SSR}{k-1}$

And $MSE=MSW=\frac{SSE}{N-k}$

The difference is that MSA takes incount the variation between the groups and the grand mean, and the MSW takes in count the variation within groups respect to the mean of each group .

And the we can find the F statistic $F=\frac{MSR}{MSE}=$

8 0

3 years ago

And object is traveling at a steady speed of 8 2/3 mph how long will it take to object to travel 5 1/5 miles

LenaWriter [7]

$\bf \begin{array}{ccll}
miles&hours\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
8\frac{2}{3}&1\\\\
5\frac{1}{5}&h
\end{array}\implies \cfrac{8\frac{2}{3}}{5\frac{1}{5}}=\cfrac{1}{h}\implies \cfrac{\quad \frac{26}{3}\quad }{\frac{26}{5}}=\cfrac{1}{h}\implies \cfrac{26}{3}\cdot \cfrac{5}{26}=\cfrac{1}{h}
\\\\\\
\cfrac{5}{3}=\cfrac{1}{h}\implies 5h=3\implies h=\cfrac{3}{5}$

which is just 36 minutes.

8 0

3 years ago

Find the midpoint of the line segment joining points A and B.<br> A(2,- 7); B(2,3)

Ad libitum [116K]

Answer: (2, -2)

Step-by-step explanation:

$\left(\frac{2+2}{2}, \frac{3-7}{2} \right)=(2,-2)$