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Hunter-Best [27]
2 years ago
15

Which ions are unlikely to form colored coordination complexes in an octahedral ligand environment? y3 fe3 cr5 ag

Chemistry
1 answer:
Zanzabum2 years ago
6 0

It is improbable that any specie with d0 or d10 will exhibit color in coordination compounds.

  • If the central metal atom or ion in a coordination complex contains unfilled d orbitals, the compound exhibits color.
  • Weak d–d transitions that produce spectral bands in the visible spectrum are thought to be the source of the colors.
  • Hence, It is improbable that any specie with d0 or d10 will exhibit color in coordination compounds.

<h3>What are coordination compounds?</h3>
  • Molecules that have one or more metal centers bonded to ligands are known as coordination compounds (atoms, ions, or molecules that donate electrons to the metal).
  • These complexes may have a charge or be neutral.
  • The complex is stabilized by nearby counter-ions when it is charged.

To learn more about coordination compounds visit:

brainly.com/question/27289242

#SPJ4

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How are chemical and mechanical weathering the same?
sasho [114]

Answer:

They break down materials into smaller pieces

Explanation:

Although using different methods

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PLZ HELP ME WITH MY WORK​
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The Gateway Arch in St. Louis, MO is approximately 630 ft tall. How many U.S. half dollars would be in a stack of the same heigh
zhannawk [14.2K]

Answer:

To equal the height of the Gateway Arch in St. Louis, it would take <u>76810 half dollars. </u>

Explanation:

If the Gateway Arch in St. Louis is 630 feet high, how many half dollars will it take to equal the height if each half dollar is 2.15mm thick?

First, we convert the ft to cm and the cm to mm.

- 1 ft = 30.48 cm

630 ft = 19202.4 cm

- 19202.4 cm = 192024 mm

Now, if a half dollar is 2.15 mm thick, how many half dollars would it take to equal the height of 192024 mm?

1 half dollar = 2.15 mm

X                 = 192024 mm

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3 years ago
Draw the mechanism for the williamson ether reaction using m-cresol and benzyl bromide (use sodium methoxide as the base).
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4 years ago
A gas sample is held at constant pressure. The gas occupies 2.97 L of volume when the temperature is 21.6°C. Determine the tempe
STALIN [3.7K]

Answer:

339.2K

Explanation:

Using Charles law equation;

V1/T1 = V2/T2

Where;

V1 = initial volume (L)

V2 = final volume (L)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information provided in this question,

V1 = 2.97 L

V2 = 3.42 L

T1 = 21.6°C = 21.6 + 273 = 294.6K

T2 = ?

Using V1/T1 = V2/T2

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Cross multiply

2.97 × T2 = 294.6 × 3.42

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T2 = 1007.532 ÷ 2.97

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The final temperature is 339.2K

5 0
3 years ago
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