What is the relationship between atoms, elements and compounds?
1 answer:
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Answer: Concentration of = 0.328 M
Concentration of = 0.328 M
Concentration of = 0.532 M
Explanation:
Moles of and
= 0.430 mole
Volume of solution = 0.500 L
Initial concentration of and
=
The given balanced equilibrium reaction is,
Initial conc. 0.860M 0.860M 0
At eqm. conc. (0.860-x) M (0.860-x) M (x) M
The expression for equilibrium constant for this reaction will be,
Now put all the given values in this expression, we get :
By solving the term 'x', we get :
x = 0.532 M
Thus, the concentrations of at equilibrium are :
Concentration of = (0.860-x) M =(0.860-0.532) M = 0.328 M
Concentration of = (0.860-x) M = (0.860-0.532) M = 0.328 M
Concentration of = x M = 0.532 M
Answer:
E = 0.062 V
Explanation:
(a) See the attached file for the answer
(b)
Calculating the voltage (E) using the formula;
E = - (2.303RT/nf)log Cathode/Anode
Where,
R = 8.314 J/K/mol
T = 35°C = 308 K
F- Faraday's constant = 96500 C/mol,
n = number of moles of electron = 2
Substituting, we have
E = -(2.303 * 8.314 *308/2*96500) *log (0.03/3)
= -0.031 * -2
= 0.062V
Therefore, the voltmeter will show a voltage of 0.062 V
