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2 years ago

3. Magnetite is a) Natural magnet (b)Artificial magnet (c) Not a magnet

Physics

2 answers:

andrey2020 [161]2 years ago

8 0

$\huge \bold \red {Aɴswᴇʀ}$

Magnetite is a Natural magnet

BARSIC [14]2 years ago

5 0

The answer would be a magnetite is a natural magnet

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A 4.0 µC point charge and a 3.0 µC point charge are a distance L apart. Where should a third point charge be placed so that the

Rudik [331]

Answer:

Q must be placed at 0.53 L

Explanation:

Given data:

q_1 = 4.0 μC , q_2 = 3.0μC

Distance between charge is L

third charge q be placed at distance x cm from q1

The force by charge q_1 due to q is

$F1 = \frac{k q q_1}{x^2}$

$F1 = \frac{k q ( 4.0 μC )}{ x^2}$ ----1

The force by charge q_2 due to q is

$F2 = \frac{k q q_2}{(L-x)^2}$

$F2 = \frac{kq (3.0 μC)}{(L-x)^2}$ --2

we know that net electric force is equal to zero

F_1 = F_2

$\frac{k q ( 4.0 μC )}{x^2} =\frac{k q ( 3.0 μC )}{(l-x)^2}$

$\frac{4}{3}*(L-x)^2 = x^2$

$x = \sqrt{\frac{4}{3}*(L - x)$

$L-x = \frac{x}{1.15}$

$L = x + \frac{x}{1.15} = 1.86 x$

x = 0.53 L

Q must be placed at 0.53 L

3 0

3 years ago

9 How can you prove that air has weight

Art [367]

Answer:

Air does, in fact, have weight, and here's a simple way you can prove it. You'll need two identical balloons, a string, and a dowel. Attach the uninflated balloons to either end of the dowel. Attach the string to the center of the dowel and then hang it from something.

Explanation:

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3 years ago

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The Lamborghini Huracan has an initial acceleration of 0.80g. Its mass, with a driver, is 1510 kg. If an 80 kg passenger rode al

irina [24]

Answer:

a = 15.1 g

Explanation:

The relation between mass and acceleration is given by :

$m\propto \dfrac{1}{a}$

If a₁ = 0.80g, m₁ = 1510 kg, m₂ = 80 kg, we need to find a₂

So,

$\dfrac{m_1}{m_2}=\dfrac{a_2}{a_1}\\\\a_2=\dfrac{a_1m_1}{m_2}\\\\a_2=\dfrac{0.8g\times 1510}{80}\\\\a_2=15.1g$

So, the car's acceleration would be 15.1 g.

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3 years ago

PLEASE ASAP ILL GIVE BRAINLIEST.

Olegator [25]

Answer:

The answer is number 2 :)

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3 years ago

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A lab cart with a mass of 15 kg is moving with constant velocity, v, along a straight horizontal track. A student drops a 2 kg m

lbvjy [14]

The equation $15v_{i} + 2*0 = (15 + 2)v_{f}$ (option 3) represents the horizontal momentum of a 15 kg lab cart moving with a constant velocity, v, and that continues moving after a 2 kg object is dropped into it.