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1 year ago

3. Magnetite is a) Natural magnet (b)Artificial magnet (c) Not a magnet

Physics

2 answers:

andrey2020 [161]1 year ago

8 0

$\huge \bold \red {Aɴswᴇʀ}$

Magnetite is a Natural magnet

BARSIC [14]1 year ago

5 0

The answer would be a magnetite is a natural magnet

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A satellite with mass 6000 kg is orbiting the planet at 2500 km above the planet's

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By the law of universal gravitation, the gravitational force F between the satellite (mass m) and planet (mass M) is

F = G M m / R ²

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Aconstant current of 3 Afor 4 hours is required to charge an automotive battery. If the terminal voltage is V, where t is in hou

kirza4 [7]

Answer:

(a) 43.2 kC

(b) 0.012V kWh

(c) 0.108V cents

Explanation:

Given:

i = current flow = 3 A
t = time interval for which the current flow = $4\ h = 4\times 3600\ s = 14400\ s$
V = terminal voltage of the battery
R = rate of energy = 9 cents/kWh

Assume:

Q = charge transported as a result of charging
E = energy expended
C = cost of charging

Part (a):

We know that the charge flow rate is the electric current flow through a wire.

$\therefore i = \dfrac{Q}{t}\\\Rightarrow Q =it\\\Rightarrow Q = 3\times 14400\\\Rightarrow Q = 43200\ C\\\Rightarrow Q = 43.200\ kC\\$

Hence, 43.2 kC of charge is transported as a result of charging.

Part (b):

We know the electrical energy dissipated due to current flow across a voltage drop for a time interval is given by:

$E = Vit\\\Rightarrow E = V\times 3\times 4\\\Rightarrow E = 12V\ Wh\\\Rightarrow E = 0.012V\ kWh\\$

Hence, 0.012V kWh is expended in charging the battery.

Part (c):

We know that the energy cost is equal to the product of energy expended and the rate of energy.

$\therefore \textrm{Cost}=\textrm{Energy}\times \textrm{Rate}\\\Rightarrow C = ER\\\Rightarrow C = 0.012V\times 9\\\Rightarrow C =0.108V\ cents$

Hence, 0.108V cents is the charging cost of the battery.

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3 years ago

3. Magnetite is a) Natural magnet (b)Artificial magnet (c) Not a magnet ​

3. Magnetite is a) Natural magnet (b)Artificial magnet (c) Not a magnet