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aniked [119]
4 years ago
9

The process by which a cell captures the energy in sunlight and uses it to make food is called

Physics
2 answers:
olga_2 [115]4 years ago
8 0
Photosynthesis- produced by a producer the capture light and convert it into glucose/ carbohydrates or "food" <span />
Lapatulllka [165]4 years ago
6 0
This is called photosynthesis
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A frame of reference is a point of set or points that.....
denis23 [38]
Describes the displace, velo, and accel of an object
8 0
3 years ago
How long would it take a leopard, running at an average speed of 20 m/s to travel 500 m?
alexandr1967 [171]

Answer:

25 seconds

Explanation:

500/20

4 0
3 years ago
X-rays with an energy of 301 keV undergo Compton scattering with a target. If the scattered X-rays are detected at 77.5^{\circ}
Alex73 [517]

Answer:

6.03\cdot 10^{-12} m

Explanation:

First of all, we need to find the initial wavelength of the photon.

We know that its energy is

E=301 keV = 4.82\cdot 10^{-14}J

So its wavelength is given by:

\lambda = \frac{hc}{E}=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{4.82\cdot 10^{-14} J}=4.13\cdot 10^{-12}m

The formula for the Compton scattering is:

\lambda' = \lambda +\frac{h}{mc}(1-cos \theta)

where

\lambda is the original wavelength

h is the Planck constant

m is the electron mass

c is the speed of light

\theta=77.5^{\circ} is the angle of the scattered photon

Substituting, we find

\lambda' = 4.13\cdot 10^{-12} m +\frac{6.63\cdot 10^{-34} Js)}{(9.11\cdot 10^{-31}kg)(3\cdot 10^8 m/s)}(1-cos 77.5^{\circ})=6.03\cdot 10^{-12} m

7 0
3 years ago
A horizontal spring is lying on a frictionless surface. One end of the spring is attaches to a wall while the other end is conne
kipiarov [429]

Answer:

0.832 m/s

Explanation:

The work done by the spring W equals the kinetic energy of the object K

The work done by the spring W = 1/2k(x₀² - x₁²) where k = spring constant, x₀   = initial compression = 0.065 m and x₁ = final compression = 0.032 m

The kinetic energy of the object, K = 1/2mv² where m = mass of object and v = speed of object

Since W = K,

1/2k(x₀² - x₁²) = 1/2mv²

k(x₀² - x₁²) = mv²

mv² = k(x₀² - x₁²)

v² = [(k/m)(x₀² - x₁²)]

taking square root of both sides, we have

v = √[(k/m)(x₀² - x₁²)] since ω = angular frequency = √(k/m),

v = √[(k/m)√(x₀² - x₁²)]

v = ω√(x₀² - x₁²)]

Since ω = 14.7 rad/s, we substitute the other variables into the equation, so we have

v = 14.7 rad/s × √((0.065 m)² - (0.032 m)²)]

v = 14.7 rad/s × √(0.004225 m² - 0.001024 m²)]

v = 14.7 rad/s × √(0.003201 m²)

v = 14.7 rad/s × 0.056577

v = 0.832 m/s

8 0
3 years ago
A car is moving at 14 m/s. After 30 s, its speed inncreased to 20 m/s. What is the acceleration over time
Juli2301 [7.4K]

Answer:

0.2 m/s^2

Explanation:

initial speed 14m/s

final speed 20m/s

acceleration:

(20m/s - 14m /s) /30s = (6m/s)/30s = 0.2 m/s^2

7 0
3 years ago
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