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Ksju [112]
3 years ago
6

Why a mirror is good for seeing objects

Physics
1 answer:
cestrela7 [59]3 years ago
3 0

Answer:

An image can be seen in the mirror because the light reflected from an object falls on the mirror and it is reflected.

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IF it possible for an object to move for 10 seconds at a high speed and end up with an average velocity of zero? true or false
marishachu [46]

True, if you move something forward at 100 miles an hour but your on something moving backwards 100 miles an hour you up staying in the same location, aka zero velocity.

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3 years ago
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A blackbody curve relates _____. intensity of radiation to energy intensity of radiation to wavelength wavelength to energy surf
neonofarm [45]

A blackbody curve represents the relation between <u>intensity of radiation with wavelength.</u>

Here in this curve we can see that all ideal blackbody radiates almost all wavelength of radiations and these radiations are of different intensity.

here intensity will be maximum for a given wavelength of radiation and the relation of this wavelength with the temperature of the object is given by Wein's law

It is given by

\lambda = \frac{b}{T}

now if we increase the temperature the maximum intensity for which wavelength is given will shift to the left.

Using this all we can also compare the temperature of two blackbody for which radiation graph is given to us.

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3 years ago
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True or false: When an object becomes polarized, it acquires a charge and becomes a charged object.​
PSYCHO15rus [73]

Answer:

i think its true

Explanation:

8 0
3 years ago
Two parallel-plate capacitors have the same plate area. Capacitor 1 has a plate separation twice that of capacitor 2, and the qu
Luba_88 [7]

Answer:

V_1=8 V_2

Explanation:

Given that:

  • Area of the plate of capacitor 1= Area of the plate of capacitor 2=A
  • separation distance of capacitor 2, d_2=d
  • separation distance of capacitor 1, d_1=2d
  • quantity of charge on capacitor 2, Q_2=Q
  • quantity of charge on capacitor 1, Q_1=4Q

We know that the Capacitance of a parallel plate capacitor is directly proportional to the area and inversely proportional to the distance of separation.

Mathematically given as:

C=\frac{k.\epsilon_0.A}{d}.....................................(1)

where:

k = relative permittivity of the dielectric material between the plates= 1 for air

\epsilon_0 = 8.85\times 10^{-12}\,F.m^{-1}

From eq. (1)

For capacitor 2:

C_2=\frac{k.\epsilon_0.A}{d}

For capacitor 1:

C_1=\frac{k.\epsilon_0.A}{2d}

C_1=\frac{1}{2} [ \frac{k.\epsilon_0.A}{d}]

We know, potential differences across a capacitor is given by:

V=\frac{Q}{C}..........................................(2)

where, Q = charge on the capacitor plates.

for capacitor 2:

V_2=\frac{Q}{\frac{k.\epsilon_0.A}{d}}

V_2=\frac{Q.d}{k.\epsilon_0.A}

& for capacitor 1:

V_1=\frac{4Q}{\frac{k.\epsilon_0.A}{2d}}

V_1=\frac{4Q\times 2d}{k.\epsilon_0.A}

V_1=8\times [\frac{Q.d}{k.\epsilon_0.A}]

V_1=8 V_2

6 0
3 years ago
Antonina throws a coin straight up from a height of
vichka [17]

Answer:

s=vt-\frac{1}{2}gt^2

Explanation:

We could use the following suvat equation:

s=vt-\frac{1}{2}gt^2

where

s is the vertical displacement of the coin

v is its final velocity, when it hits the water

t is the time

g is the acceleration of gravity

Taking upward as positive direction, in this problem we have:

s = -1.2 m

g=-9.8 m/s^2

And the coin reaches the water when

t = 1.3 s

Substituting these data, we can find v:

v=\frac{s}{t}+\frac{1}{2}gt=-\frac{1.2}{1.3}+\frac{1}{2}(-9.8)(1.3)=-7.3 m/s

where the negative sign means the direction is downward.

5 0
3 years ago
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