During the first 6 years of its operation, the Hubble Space Telescope circled the Earth 37,000 times, for a total of 1,280,000,0
1 answer:
Answer:
Explanation:
Given Data:
Numbers of times Telescope cycled around the earth in 6 years=37,000 times
Total Distance traveled in 6 years by the Hubble Space Telescope=1,280,000,000 Km
Find:
Kilometers in one Orbit=?
Solution:
Kilometers in 37,000 Orbits=1,280,000,000 Km
Kilometers in 1 Orbit=1,280,000,000/37,000
In Scientific Notation:
Kilometers in 1 Orbit=34594.594 Km
Kilometers in 1 Orbit in Scientific notation:
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Answer:
150000000000 m
0.0000005 seconds
33.33 ns
Explanation:
Speed of electromagnetic waves through vacuum =
Echo time = 1000 seconds
Echo time is the time taken to reach the object and come back to the observer
Distance = Speed×Time
Venus is 150000000000 m away from Earth
Time = Distance / Speed
Echo time will be twice the time
The echo time will be 0.0000005 seconds
Difference in time = Difference in distance / Speed
The accuracy by which I will be able to measure the echo time is 33.33 ns
To solve this problem we will apply the definitions given in Newtonian theory about the Force of gravity, and the Force caused by weight. Both will be defined below, and in equal equilibrium condition to clear the variable concerning acceleration due to gravity. Finally, with the values provided in the statement, it will be replaced.
The equation for the gravitational force between the Earth and the object on the surface of the Earth is
Where,
G = Universal gravitational constant
= Mass of Earth
= Distance between object and center of earth
= Mass of Object
The equation for the gravitational pulling force on the object due to gravitational acceleration is
Equation the two expression we have
This the acceleration due to gravity which is composite constant.
Replacing with our values we have then
The value of composite constant is . Here, the composite constant is nothing but the acceleration due to gravity which is constant always.