1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
densk [106]
2 years ago
6

Balance the following skeleton reactions and identify the oxidizing and reducing agents:(b) P₄(s) → HPO₃²⁻(aq) + PH₃(g) [acidic]

Chemistry
1 answer:
m_a_m_a [10]2 years ago
5 0

The balanced chemical equation is :

5P₄ + 36OH → 12HPO₃⁻² (aq) + 8PH₃ (acidic)

Here the oxidation number of P changed from 0 to -3 in PH₃ and increases  from 0 to +3 in HPO₃⁻². When P₄ changes to PH₃ reduction reaction is taking place as there is addition of hydrogen and when P₄ changes to HPO₃⁻² oxidation takes place as there is addition of oxygen.

Thus clearly both reduction and oxidation are taking place.

Thus, we can infer that here P₄ is both oxidizing as well as reducing agent.

To know more about oxidation number here:

brainly.com/question/13182308

#SPJ4

You might be interested in
Someone please help me, the picture is shown above !
Agata [3.3K]
The quality of being easily dissolved in liquid.

Hope this help and Happy holidays
3 0
3 years ago
Read 2 more answers
What is the oxidation half-reaction for this unbalanced redox equation? cr2o72– + fe2+ → cr3+ + fe3+ cr3+ → cr2o72– cr2o72– → cr
KatRina [158]

Answer:

6Fe^2+(aq) -------> 6Fe^3+(aq) + 6e

Explanation:

The balanced oxidation half equation is;

6Fe^2+(aq) -------> 6Fe^3+(aq) + 6e

A redox reaction is actually an acronym for oxidation-reducation reaction. Since the both reactions are complementary, there can't be oxidation without reduction and there can't be reduction without oxidation.

The main characteristic of redox reactions is that electrons are transferred in the process. The number of electrons transferred is usually deduced from the balanced reaction equation. For this reaction, the balanced overall reaction equation is;

Cr2O7^2–(aq) + 6Fe^2+(aq) +14H^+(aq)→ 2Cr^3+(aq) + 6Fe^3+ (aq) + 7H2O(l)

It is clear from the equation above that six electrons were transferred. Thus six Fe^2+ ions lost one electron each in the oxidation half equation as shown in the balanced oxidation half equation above.

4 0
3 years ago
Can anyone help me on this please?
Bad White [126]
This question is testing to see how well you understand the "half-life" of radioactive elements, and how well you can manipulate and dance around them.  This is not an easy question.

The idea is that the "half-life" is a certain amount of time.  It's the time it takes for 'half' of the atoms in any sample of that particular unstable element to 'decay' ... their nuclei die, fall apart, and turn into nuclei of other elements.

Look over the table.  There are 4,500 atoms of this radioactive substance when the time is 12,000 seconds, and there are 2,250 atoms of it left when the time is ' y ' seconds.  Gosh ... 2,250 is exactly half of 4,500 !  So the length of time from 12,000 seconds until ' y ' is the half life of this substance !  But how can we find the length of the half-life ? ? ?

Maybe we can figure it out from other information in the table !

Here's what I found:

Do you see the time when there were 3,600 atoms of it ? 
That's 20,000 seconds.

... After one half-life, there were 1,800 atoms left.
... After another half-life, there were 900 atoms left.
... After another half-life, there were 450 atoms left. 

==>  450 is in the table !  That's at 95,000 seconds.

So the length of time from 20,000 seconds until 95,000 seconds
is three half-lifes.

The length of time is (95,000 - 20,000) = 75,000 sec

                                     3 half lifes = 75,000 sec

Divide each side by 3 :   1 half life = 25,000 seconds

There it is !  THAT's the number we need.  We can answer the question now.

==> 2,250 atoms is half of 4,500 atoms.

==> ' y ' is one half-life later than 12,000 seconds

==> ' y ' = 12,000 + 25,000

         y   = 37,000 seconds  .

Check: 
Look how nicely 37,000sec fits in between 20,000 and 60,000 in the table.

As I said earlier, this is not the simplest half-life problem I've seen.
You really have to know what you're doing on this one.  You can't
bluff through it.


7 0
4 years ago
Óxido cuprico+amoniaco-------Nitrógeno +cobre +agua(redox)
tigry1 [53]

Answer:

?? no entiendo la pregunta?...pero gracias por los puntos free UvU

Explanation:

3 0
3 years ago
Which of the following uses a nonrenewable energy resource to generate energy? A. nuclear power plant B. wind farm C. fireplace
Alisiya [41]
A & C.
much debated nuclear power plants uses nuclear fission power stations, with uranium-235 as the source if fission. It is "non-renewable" according to the Energy Information Administration.

burning wood is also a non-renewable energy source
6 0
3 years ago
Read 2 more answers
Other questions:
  • Suppose that atom x undergoes radioactive decay that results in atom y. If y has a larger atomic number than x, which type of ra
    13·1 answer
  • How many atoms are in 2.50 mol of hydrogen?
    13·2 answers
  • Consider the ionic compound that is the combination of the Chromium (III) and hydroxide ions. How many chromium atoms would be p
    12·1 answer
  • Does this change in temperature of the water and the mixing of liquids in the calorimeter represent an increase or decrease in e
    15·1 answer
  • Filtration, devastation, and evaporation are examples of
    7·1 answer
  • How do you calculate bonding capacity in chemistry?
    8·1 answer
  • What is is 0.000431 as an integer?
    5·1 answer
  • Which statement is true about a proton and an electron?
    13·1 answer
  • There are three ways in which heat be transferred - conduction, convection, and radiation. Which types of thermal transfer invol
    7·1 answer
  • Assume that the ratio of moles of Cl to moles of Cu are 2.39. If we can represent the formula by CuClx, what is the value for x?
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!