The complete balanced reaction for this would be:H3PO4 + 3NaOH ---> Na3PO4 + 3H2OSo we can see that 3 moles of NaOH reacts with 1 mole of H3PO4.
moles NaOH = 0.2 M * 0.05 L = 0.01 molesmoles H3PO4 = 0.01 moles NaOH * (1 mole H3PO4 / 3 moles NaOH) = 0.00333 moles
So the volume required would be:V = 0.00333 moles / (0.200 moles / L)V = 0.0167 L = 16.7 mL
Answer:
The reaction is endothermic.
Yes, absorbed
3.06x10¹kJ are absorbed
Explanation:
In the reaction:
2HgO(s) → 2Hg(l) + O₂(g) ΔH = 182kJ
As ΔH >0,
<em>The reaction is endothermic</em>
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As the reaction is endothermic, when the reaction occurs,
<em>the heat is absorbed.</em>
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Now, based on the equation, when 2 moles of HgO (Molar mass: 216.59g/mol), 182kJ are absorbed.
72.8g are:
72.8g * (1mol / 216.59g) = 0.3361 moles HgO.
that absorb:
0.3361 moles HgO * (182kJ / 2 moles) =
<h3>3.06x10¹kJ are absorbed</h3>
Answer: -
Group 5 - Metalliods.
Group 7 - Halogens Group
Group 8 - Noble Gases
Explanation: -
Group 1 are the alkali metals.
Group 2 are the alkaline earth metals.
Group 5 are a part of transition metals which range from Group 3 to Group 12.
Group 17 are the halogens.
Group 18 are the noble gases.