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Archy [21]
2 years ago
15

A 8L sample of gas at 250 K is cooled to 75 K. What is the volume of the gas after it is cooled?

Chemistry
1 answer:
Stells [14]2 years ago
7 0

by \: Charles'\: law: \:  \\  \frac{v_{1}}{t_{1}}  =  \frac{v_{2}}{t_{2}}  \\

Where v is the volume(in L) and t is the temperature(in °K)

\frac{8}{250}  =  \frac{v_{2}}{75} \\\\4/5 =v_2/3 \\\\\boxed{v_{2} = \frac{12}{5}}\\\\\\\huge{=2.5 l}

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An unknown liquid has a mass of 30.8 g, and a volume of 31.5 mL. What is the density of this liquid?
julsineya [31]

The density of the liquid is 0.98 g/mL

<h3>What is density? </h3>

The density of a substance is defined as the mass of the subtance per unit volume of the substance. Mathematically, it can be expressed as:

Density = mass / volume

With the above formula, we can obtain the density of the liquid.

<h3>How to determine the density </h3>
  • Mass = 30.8 g
  • Volume = 31.5 mL
  • Density =?

Density = mass / volume

Density of liquid = 30.8 / 31.5

Density of liquid = 0.98 g/mL

Learn more about density:

brainly.com/question/952755

3 0
2 years ago
I’m not sure what the answer is
Sergio [31]
I believe it’s the third option
Chemically combined to make a new pure substance
7 0
3 years ago
Read 2 more answers
Determine the mass of CaCO3 required to produce 40.0 mL CO2 at STP. Hint use molar volume of an ideal gas (22.4 L)
cupoosta [38]

Answer:

m_{CaCO_3}=0.179gCaCO_3

Explanation:

Hello,

In this case, since the undergoing chemical reaction is:

CaCO_3(s)\rightarrow CaO(s)+CO_2(g)

The corresponding moles of carbon dioxide occupying 40.0 mL (0.0400 L) are computed by using the ideal gas equation at 273.15 K and 1.00 atm (STP) as follows:

PV=nRT\\\\n=\frac{PV}{RT}=\frac{1.00 atm*0.0400L}{0.082\frac{atm*L}{mol*K}*273.15 K})=1.79x10^{-3} mol CO_2

Then, since the mole ratio between carbon dioxide and calcium carbonate is 1:1 and the molar mass of the reactant is 100 g/mol, the mass that yields such volume turns out:

m_{CaCO_3}=1.79x10^{-3}molCO_2*\frac{1molCaCO_3}{1molCO_2} *\frac{100g CaCO_3}{1molCaCO_3}\\ \\m_{CaCO_3}=0.179gCaCO_3

Regards.

3 0
3 years ago
Which of these are elimination reactions? Check all that apply.
kotykmax [81]

Answer:

C3H7OH → C3H6 + H20

Explanation:

If we look at the reactant and the product we will realize that the reactant is an alcohol while the product is an alkene. The reaction involves acid catalysed elimination of water from an alcohol.

Water is a good leaving group, hence an important synthetic route to alkenes is the acid catalysed elimination of water from alcohols. Hence the conversion represented by C3H7OH → C3H6 + H20 is an elimination reaction in which water is the leaving group.

7 0
3 years ago
What is the hydrogen ion concentration of a solution with pH=8.25 ?
77julia77 [94]

Answer:

The answer is

<h2>5.62 \times  {10}^{ - 9} \:  M</h2>

Explanation:

The pH of a solution can be found by using the formula

pH =  -  log( {H}^{ + } )

where

{H}^{ + } is the hydrogen ion concentration of the solution

From the question

pH = 8.25

The hydrogen ion concentration of the solution is

8.25 =  -  log( {H}^{ + } )

<u>Find antilog of both sides</u>

That's

{H}^{ + }  =  {10}^{ - 8.25}  \\  = 5.62 \times  {10}^{ - 9} \:  M

We have the final answer as

5.62 \times  {10}^{ - 9} \:  M \\

Hope this helps you

5 0
3 years ago
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