Question

A 8L sample of gas at 250 K is cooled to 75 K. What is the volume of the gas after it is cooled?

Answer 1

$by \: Charles'\: law: \: \\ \frac{v_{1}}{t_{1}} = \frac{v_{2}}{t_{2}}$

Where v is the volume(in L) and t is the temperature(in °K)

$\frac{8}{250} = \frac{v_{2}}{75} \\\\4/5 =v_2/3 \\\\\boxed{v_{2} = \frac{12}{5}}\\\\\\\huge{=2.5 l}$