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mote1985 [20]
1 year ago
5

If the temperature dropped by 7.f each hour from 5:00 am to 9:00 am. What was the beginning temperature at 5:00 am if the temper

ature at 9:00 am was -10.f?
Mathematics
1 answer:
arlik [135]1 year ago
4 0

If the temperature dropped by 7.f each hour from 5:00 am to 9:00 am.  the beginning temperature at 5:00 am if the temperature at 9:00 am was -10.f is 18.f.

<h3>Beginning temperature</h3>

Dropped in temperature=7.t

Number of hours= 5:00 am to 9:00 am=4 hours

Temperature at 9:00 am=-10.f

Hence:

Beginning temperature can be calculated as:

Beginning temperature=(4× 7) + (-10)

Beginning temperature=28 + (-10)

Beginning temperature= 18.f

Check:

Since  temperature dropped by 7.f each hour from 5:00 am to 9:00 am

which implies that temperature  7.f dropped for 4 hours.

Hence:

18-7-7-7-7=-10.f

Therefore If the temperature dropped by 7.f each hour from 5:00 am to 9:00 am.  the beginning temperature at 5:00 am if the temperature at 9:00 am was -10.f is 18.f.

Learn more about Beginning temperature here:brainly.com/question/24746268

#SPJ1

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Answer:

f(-1) = -2

Step-by-step explanation:

Given

The attached graph

Required

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On the attached graph;

f(x) = -2 when x = -1

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f(-1) = -2

8 0
2 years ago
Jason and Alison are hiking in the woods when they spot a rare owl in a tree. Jason stops and measures an angle of elevation of
Shalnov [3]

Answer:

Owl= 67.14ft

Step-by-step explanation:

<em>See comment for complete question.</em>

The given information is represented in the attached figure.

First convert 22°8'6'' and 30° 40’ 30” to degrees

22^{\circ} 8'6'' = 22 + \frac{8}{60} + \frac{6}{3600}

22^{\circ} 8'6'' = 22.135^{\circ}

30^{\circ} 40'30'' = 30 + \frac{40}{60} + \frac{30}{3600}

30^{\circ} 40'30'' = 30.675^{\circ}

Considering Jason's position:

tan(22.135^{\circ}) = \frac{H}{x + 48}

Where x = distance between the tree and Alison

Make H the subject

H = (x + 48)tan(22.135^{\circ})

Considering Alison's position

tan(30.675^{\circ}) = \frac{H}{x}

Make H the subject

H = xtan(30.675^{\circ})

H = H

(x + 48)tan(22.135^{\circ}) = xtan(30.675^{\circ})

(x + 48) *0.4068 = x* 0.5932

Open bracket

x *0.4068 + 48 *0.4068 = 0.5932x

0.4068x + 19.5264 = 0.5932x

Collect Like Terms

-0.5932x+0.4068x = -19.5264

-0.1864x = -19.5264

0.1864x = 19.5264

Make x the subject

x = \frac{19.5264}{0.1864}

x = 104.76

Substitute 104.76 for x in H = xtan(30.675^{\circ})

H = 104.76 * tan(30.675^{\circ})

H = 104.76 * 0.5932

H = 62.14

The above represents the height of the tree.

The height of the owl is:

Owl= H + 5

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Owl= 67.14ft

7 0
2 years ago
Need help ASAP
Margarita [4]
<span>Angle T = Angle C, let them equal x

So x + x + 140 = 180

2x = 40

x = 20

So Angle T = 20 degrees </span>
6 0
3 years ago
Find the area. Round to the nearest tenth.<br>6 ft<br>3 ft<br>12.16 ft<br>9.16 ft<br>​
bagirrra123 [75]

Answer:

100.5 ft^2

Step-by-step explanation:

First find the area of the rectangle

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A = 12.16 * 6

A =72.96 ft^2

Then find the area of the triangle

A = 1/2 bh

The base is 12 ft - 6ft = 6ft

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A = 1/2 ( 9.16) * 6

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Add them together

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Round to the nearest tenth

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7 0
3 years ago
Read 2 more answers
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RSB [31]
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7 0
3 years ago
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