1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
s2008m [1.1K]
2 years ago
15

Two parallel wires are separated by 6.00 cm, each carrying 3.00 A of current in the same direction.(b) Is the force attractive o

r repulsive?
Physics
1 answer:
Aleonysh [2.5K]2 years ago
4 0

The force is attractive.

The force between two parallel currents I₁ and I₂ that are spaced apart by r is measured as the ratio F/L. If the currents are flowing in the same direction, the force is attracting; if not, it is repulsive.

Each parallel wire carries 3.00 A of current in the same direction and is spaced apart by 6.00 cm.

Think of these two wires as being placed side by side on a table, with currents flowing in opposite directions toward you—wire 1 to the left and wire 2 to the right. The magnetic field produced by wire 1 at the location of wire 2 is directed vertically upward, according to the right-hand rule that links current to field direction. The force experienced by wire 2 as a result of its current flowing through this field is therefore determined by the right-hand rule, which links current and field to force, to be to the left, back toward wire 1. The force that one wire applies to another is therefore an attractive force.

Learn more about force here:

brainly.com/question/12970081

#SPJ4

You might be interested in
A force platform is a tool used to analyze the performance of athletes measuring the vertical force that the athlete exerts on t
Phoenix [80]

Answer:

a.I=981.34 N*s

b.v_f=3.96 m/s

c.v_{f1}=3.63m/s

d.y_f=0.673m

Explanation:

Given: m=67kg, h=0.720m, 0

a.

I=\int\limits^{t_1}_{t_2} {F(t)} \, dt

F(t)=9200*t-11500t^2

I=\int\limits^{0.8s}_{0s}{9200*t-11500*t^2} \, dt

I=4600*t^2-3833.3*t^3|(0.80,0)

I=2944-1962.66=981.35

I=981.34 N*s

b.

v_f^2=v_i^2+a*y'

Starting from the rest

v_f^2=0+2*9.8m/s^2*0.80s

v_f^2=15.68

v_f=\sqrt{15.68m^2/s^2}=3.96 m/s

c.

I_{total}=p_f

I_1-m*g*d=m*v_{f1}-m*v_f

981.34-67kg*9.8m/s^2*0.720=67.0kg*v_{f1}-67.0kg*(-3.96m/s)

Solve to vf

v_{f1}=3.63m/s

d.

v_f^2=v_i^2+2*a*y_f'

y_f'=v_i/2*a =(3.63m/s)^2/2*9.8m/s^2

y_f=0.673m

7 0
3 years ago
Un the way to the moon, the Apollo astro-
kherson [118]

Answer:

Distance =  345719139.4[m]; acceleration = 3.33*10^{19} [m/s^2]

Explanation:

We can solve this problem by using Newton's universal gravitation law.

In the attached image we can find a schematic of the locations of the Earth and the moon and that the sum of the distances re plus rm will be equal to the distance given as initial data in the problem rt = 3.84 × 108 m

r_{e} = distance earth to the astronaut [m].\\r_{m} = distance moon to the astronaut [m]\\r_{t} = total distance = 3.84*10^8[m]

Now the key to solving this problem is to establish a point of equalisation of both forces, i.e. the point where the Earth pulls the astronaut with the same force as the moon pulls the astronaut.

Mathematically this equals:

F_{e} = F_{m}\\F_{e} =G*\frac{m_{e} *m_{a}}{r_{e}^{2}  } \\

F_{m} =G*\frac{m_{m}*m_{a}  }{r_{m} ^{2} } \\where:\\G = gravity constant = 6.67*10^{-11}[\frac{N*m^{2} }{kg^{2} } ] \\m_{e}= earth's mass = 5.98*10^{24}[kg]\\ m_{a}= astronaut mass = 100[kg]\\m_{m}= moon's mass = 7.36*10^{22}[kg]

When we match these equations the masses cancel out as the universal gravitational constant

G*\frac{m_{e} *m_{a} }{r_{e}^{2}  } = G*\frac{m_{m} *m_{a} }{r_{m}^{2}  }\\\frac{m_{e} }{r_{e}^{2}  } = \frac{m_{m} }{r_{m}^{2}  }

To solve this equation we have to replace the first equation of related with the distances.

\frac{m_{e} }{r_{e}^{2}  } = \frac{m_{m} }{r_{m}^{2} } \\\frac{5.98*10^{24} }{(3.84*10^{8}-r_{m}  )^{2}  } = \frac{7.36*10^{22}  }{r_{m}^{2} }\\81.25*r_{m}^{2}=r_{m}^{2}-768*10^{6}* r_{m}+1.47*10^{17}  \\80.25*r_{m}^{2}+768*10^{6}* r_{m}-1.47*10^{17} =0

Now, we have a second-degree equation, the only way to solve it is by using the formula of the quadratic equation.

r_{m1,2}=\frac{-b+- \sqrt{b^{2}-4*a*c }  }{2*a}\\  where:\\a=80.25\\b=768*10^{6} \\c = -1.47*10^{17} \\replacing:\\r_{m1,2}=\frac{-768*10^{6}+- \sqrt{(768*10^{6})^{2}-4*80.25*(-1.47*10^{17}) }  }{2*80.25}\\\\r_{m1}= 38280860.6[m] \\r_{m2}=-2.97*10^{17} [m]

We work with positive value

rm = 38280860.6[m] = 38280.86[km]

<u>Second part</u>

<u />

The distance between the Earth and this point is calculated as follows:

re = 3.84 108 - 38280860.6 = 345719139.4[m]

Now the acceleration can be found as follows:

a = G*\frac{m_{e} }{r_{e} ^{2} } \\a = 6.67*10^{11} *\frac{5.98*10^{24} }{(345.72*10^{6})^{2}  } \\a=3.33*10^{19} [m/s^2]

6 0
3 years ago
How does the movement of particles of matter change when matter goes from solid to liquid?
icang [17]
Solid to liquid: molecules spread out to have their own spaces and move energetic and lively.
5 0
4 years ago
When is the kinetic energy of an electron transformed into potential energy?
8090 [49]

Answer:

when it interacts with other electrons without changing its speed

Explanation:

without changing its speed

4 0
3 years ago
What type of nuclear decay releases energy but not a particle?
statuscvo [17]
I believe gamma decay but i may be wrong
7 0
3 years ago
Read 2 more answers
Other questions:
  • A wheel rotates through 5.7 rad in 2.6 s as it is brought to rest with constant angular acceleration. Determine the wheel's init
    11·1 answer
  • Which is the correct symbol for an isotope of helium with 2 neutrons?
    11·1 answer
  • The average braking force of a 1000-kg car moving at 10 m/s braking to a stop in 5 s is
    12·1 answer
  • Which of the following is NOT an example of a force?
    13·1 answer
  • - In Einstein's famous equation E = me?, describing the
    9·1 answer
  • You have trained all year for a marathon. In your first attempt to run a marathon, you decide that you want to complete this 26-
    14·1 answer
  • SOMEONE PLEASE HELP FAST
    6·1 answer
  • Kepler's laws and explanations​
    6·2 answers
  • 8) The radius of the moon is approximately 1,350,000 m. What is the radius in centimeters? (100cm = 1m)
    9·1 answer
  • If you committed a crime, would it be easy for investigators to match this print to your records? Why or why not? Hint: how’s th
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!