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kakasveta [241]
3 years ago
6

Kepler's laws and explanations​

Physics
2 answers:
IgorC [24]3 years ago
5 0

Answer:

<em>The first law states that</em> every planet describes an elliptical path about the sun as a single focus.

<em>The</em><em> </em><em>second</em><em> </em><em>law</em><em> </em><em>states</em><em> </em><em>that</em><em> </em>The line joining the planet to the sun sweeps out equal areas in equal time intervals.

<em>The</em><em> </em><em>third</em><em> </em><em>law</em><em> </em><em>states</em><em> </em><em>that</em><em> </em>The squares of the period of revolution is proportional to the cubes of the mean distance between the planet and the sun

saul85 [17]3 years ago
5 0
Kepler's Law of equal areas for equal times. As a planet moves in an orbit about the Sun, the areas swept out by the planet are equal for equal time intervals. A: For circular orbits the equal areas are identical in shape and size (red areas).
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Answer:

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The vertical force f acts downward at A on the two membered frames. Determine the magnitude of the two components of F directed
galben [10]

Answer:

The magnitude will be "353.5 N". A further solution is given below.

Explanation:

The given values is:

F = 500 N

According to the question,

In ΔABC,

⇒ \angle BCA = (90-30)

⇒             =60^{\circ}

then,

⇒ \angle BAC=(180-45-60)

⇒             =75^{\circ}

Now,

The corresponding angle will be:

⇒ \angle FAC=60^{\circ}

⇒ \angle FAB=70+60

⇒             =135^{\circ}

Aspect of F across the AC arm will be:

= F\times cos(60)

On putting the values of F, we get

= 500\times (.5)

= 200 \ Newton

Component F along the AC (in magnitude) will be:

= F\times cos(135)

= 500\times (-.707)

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3 years ago
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3 years ago
A 1000-kg car is driving toward the north along a straight horizontal road at a speed of 20.0 m/s. The driver applies the brakes
Nitella [24]

Answer:

The value of F= - 830 N

Since the force is negative, it implies direction of the force applied was due south.

Explanation:

Given data:

Mass = 1000-kg

Distance, d = 240 m

Initial velocity, v1 = 20.0 m/s

Final velocity, v2 = 0 (since the car came to rest after brake was applied)

v2²= v1² + 2ad (using one of the equation of motion)

0=  20² + (2 x a x  240)

0= 400 + 480 a

a = - 400/480

a = - 0.83 m/s²

Then, imputing the value of a into

F = ma

F = 1000 kg x ( - 0.83 m/s²)

F= - 830 N

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3 years ago
Answer all please!!!!!!!!!!✌​
Nina [5.8K]

Answer:

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Explanation:

7 0
3 years ago
Read 2 more answers
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