What type of nuclear decay releases energy but not a particle?
2 answers:
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Answer:
A) K / K₀ = 4 b) v / v₀ = 4
Explanation:
A) For this exercise we can use the conservation of mechanical energy
in the problem it indicates that the displacement was doubled (x = 2xo)
starting point. At the position of maximum displacement
Em₀ = Ke = ½ k (2x₀)²
final point. In the equilibrium position
= K = ½ m v²
Em₀ = Em_{f}
½ k 4 x₀² = K
(½ K x₀²) = K₀
K = 4 K₀
K / K₀ = 4
B) the speed value
½ k 4 x₀² = ½ m v²
v = 4 (k / m) x₀
if we call
v₀ = k / m x₀
v = 4 v₀
v / v₀ = 4
Simply, apply the formula 
and insert the values of m = mass, v = velocity and E = Energy.
The result will be
, m = 1 kg
The result will be
Answer:
Explanation:
The fundamental charge of a single electron is .
If there are 10 excess electrons, the net charge that would be measured should be 10 times the fundamental charge of a single electron: