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Ostrovityanka [42]
3 years ago
11

What type of nuclear decay releases energy but not a particle?

Physics
2 answers:
statuscvo [17]3 years ago
7 0
I believe gamma decay but i may be wrong
Simora [160]3 years ago
3 0
It would be gamma decay
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A transverse, wave travelling on a chord is represented by D=0.22sin (5.6x+34t) where D and x are inmeters and t is in seconds.
ArbitrLikvidat [17]

Answer:

a) λ = 1.12 m

b) f = 5.41 Hz

c) v = 154.54 m/s

d) A = 0.22m

e)

v_D_{max}=7.48\frac{m}{s}\\\\v_D_{min}=-7.48\frac{m}{s}\\\\

Explanation:

You have the following equation for a wave traveling on a cord:

D=0.22sin(5.6x+34t)     (1)

The general expression for a wave is given by:

D=Asin(kx-\omega t)    (2)

By comparing the equation (1) and (2) you have:

A: amplitude of the wave = 0.22m

k: wave number = 5.6 m^-1

w: angular velocity = 34 rad/s

a) The wavelength is given by substitution in the following expression:

\lambda=\frac{2\pi}{k}=\frac{2\pi}{5.6m^{-1}}=1.12m

b) The frequency is:

f=\frac{\omega}{2\pi}=\frac{34s^{-1}}{2\pi}=5.41Hz

c) The velocity of the wave is:

v=\frac{\omega}{k}=\frac{34s^{-1}}{0.22m^{-1}}=154.54\frac{m}{s}

d) The amplitude is 0.22m

e) To calculate the maximum and minimum speed of the particles you obtain the derivative of  the equation of the wave, in time:

v_D=\frac{dD}{dt}=(0.22)(34)cos(5.6x+34t)\\\\v_D=7.48cos(5.6x+34t)

cos function has a minimum value -1 and maximum +1. Then, you obtain for maximum and minimum velocity:

v_D_{max}=7.48\frac{m}{s}\\\\v_D_{min}=-7.48\frac{m}{s}\\\\

6 0
3 years ago
1When you look through a magnifying glass, the objects you are looking at
Vadim26 [7]

convex lenses.

eyeglasses with convex lenses increase refraction, and accordingly reduce the focal lenght

8 0
3 years ago
In a dairy operation, milk at a flow rate of 250 L/h and a cow-body temperature of 38.6 °C must be chilled to a safe-to-store te
Anit [1.1K]

Answer: idk

Explanation:

6 0
3 years ago
A 1750 kg Ford Mustang Convertible and a 2222 kg Dodge Ram 4x4 truck were involved in a head on car crash. The Mustang initially
Zepler [3.9K]

Answer:

-1.3 m/s

Explanation:

It won't allow me submit, so be good to check the attachment

3 0
3 years ago
The bonds of oxygen molecules are broken by sunlight. The minimum energy required to break the oxygen-oxygen bond is 495 kJ/mol.
makvit [3.9K]

Answer:

The wavelength of sunlight that can cause this bond breakage is 242 nm

Explanation:

The minimum energy of the sunlight that'll break Oxygen-oxygen bond must match 495 KJ/mol

But 1 mole of any molecule contains 6.02 × 10²³ molecules/mol

Each molecule of Oxygen will require (495 × 10³)/(6.02 × 10²³) = 8.22 × 10⁻¹⁹ J

E = hf

v = fλ

f = v/λ

f = frequency of the sunlight

λ = wavelength of the sunlight

v = speed of light = 3.0 × 10⁸ m/s

E = hv/λ

λ = hv/E

h = Planck's constant = 6.63 × 10⁻³⁴ J.s

λ = (6.63 × 10⁻³⁴)(3 × 10⁸)/(8.22 × 10⁻¹⁹)

λ = 2.42 × 10⁻⁷ m = 242 nm.

5 0
3 years ago
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