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Andre45 [30]
1 year ago
8

what will its intensity be after passing through a polarizing filter with its axis at an 84° angle relative to the light’s polar

ization direction? give your answer in terms of mw/m2.
Physics
1 answer:
aleksandr82 [10.1K]1 year ago
4 0

The intensity after passing the polarizing filter is 0.1 Ii W/m².

We need to know about polarizator to solve this problem. Polarizator is a device that polarizes the electromagnetic wave from light. The intensity of light after polarizator can be determined as

It = Ii . cosθ

where It is the intensity of light after polarizator, Ii is the intensity of the light source, and θ is the angle of the light source.

From the question above, we know that:

θ = 84⁰

We can determine the intensity after polarizing filter with the equation

It = Ii . cosθ

It = Ii . cos(84⁰)

It = 0.1 Ii W/m²

where Ii is intensity of the light source

Hence, the intensity after passing the polarizing filter is 0.1 Ii W/m².

Find more on polarizator at: brainly.com/question/1444040

#SPJ4

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When looking into a tall glass of tea, you observe the tea looks darker when looking from top to bottom than when looking from t
IgorLugansk [536]

Answer:

The correct answer is b. Differences in Path Lenght

Explanation:

In this area of knowledge, there two main ways of referring to Path Lenght:

1. The total distance an object travels from a starting point, without considering trajectory.

2.  When talking about wavelength, because this relates to light and how it travels throughout different mediums. This concept is used in calculating constructive and destructive interference of waves, and is responsible for seeing different shades of tea color.

Hope this helps!

8 0
4 years ago
5. George walks to a friend's house. He walks 750 meters North, then realizes he walked too far.
dedylja [7]

Answer:

Average speed: approximately 76.9\; {\rm m\cdot s^{-1}}.

Average velocity: approximately 38.5\; {\rm m \cdot s^{-1}} (to the north.)

Explanation:

Consider an object that travelled along a certain path. Distance travelled would be equal to the length of the entire path.

In contrast, the magnitude of displacement is equal to distance between where the object started and where it stopped.

In this question, the path George took required him to travel 750\; {\rm m} + 250\; {\rm m} = 1000\; {\rm m} in total. Hence, the distance George travelled would be 1000\; {\rm m}. However, since George stopped at a point (750\; {\rm m} - 250\; {\rm m}) = 500\; {\rm m} to the north of where he started, his displacement would be only 500\; {\rm m} to the north.

Divide total distance by total time to find the average speed.

Divide total displacement by total time to find average velocity.

The total time of travel in this question is 13\; {\rm s}.. Therefore:

\begin{aligned}\text{average speed} &= \frac{\text{total distance}}{\text{total time}} \\ &= \frac{1000\; {\rm m}}{13\; {\rm s}} \\ &\approx 76.9\; {\rm m\cdot s^{-1}}\end{aligned}.

\begin{aligned}\text{average velocity} &= \frac{\text{total displacement}}{\text{total time}} \\ &= \frac{500\; {\rm m}}{13\; {\rm s}} && \genfrac{}{}{0px}{}{(\text{to the north})}{}\\ &\approx 38.5\; {\rm m\cdot s^{-1}} && (\text{to the north})\end{aligned}.

3 0
2 years ago
Diamond is the one mineral in the world that cannot be scratched by any other mineral. Therefore, we refer to diamond as the ___
mart [117]

Answer:

hardest

Explanation:

Diamonds are known as the hardest naturally occurring substance known.

4 0
3 years ago
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1. What three particles are found in an atom?
Hoochie [10]

Answer:

Protons, Electrons, and neutrons

7 0
4 years ago
Read 2 more answers
A ball is dropped off a very tall canyon ledge.
oksano4ka [1.4K]

Answer:

V = 49.05 [m/s]

Explanation:

We can easily find the result using kinematics equations, first, we will find the distance traveled during the 5 seconds.

y =y_{o}+(v_{o}*t)+(\frac{1}{2}*g*t^{2} )

where:

Yo = initial position = 0

y = final position [m]

Vo = initial velocity = 0

t = time = 5 [s]

g = gravity aceleration = 9.81 [m/s^2]

The initial speed is zero, as the body drops without imparting an initial speed. Therefore:

y = 0 + (0*5) + (0.5*9.81*5^2)

y = 122.625[m]

Now using the following equation we can find the speed it reaches during the 5 seconds.

v_{f} ^{2}= v_{i} ^{2}+(2*g*y)\\v_{f}=\sqrt{2*9.81*122.625} \\v_{f}=49.05 [m/s]

6 0
4 years ago
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