Answer:
The correct answer is b. Differences in Path Lenght
Explanation:
In this area of knowledge, there two main ways of referring to Path Lenght:
1. The total distance an object travels from a starting point, without considering trajectory.
2. When talking about wavelength, because this relates to light and how it travels throughout different mediums. This concept is used in calculating constructive and destructive interference of waves, and is responsible for seeing different shades of tea color.
Hope this helps!
Answer:
Average speed: approximately
.
Average velocity: approximately
(to the north.)
Explanation:
Consider an object that travelled along a certain path. Distance travelled would be equal to the length of the entire path.
In contrast, the magnitude of displacement is equal to distance between where the object started and where it stopped.
In this question, the path George took required him to travel
in total. Hence, the distance George travelled would be
. However, since George stopped at a point
to the north of where he started, his displacement would be only
to the north.
Divide total distance by total time to find the average speed.
Divide total displacement by total time to find average velocity.
The total time of travel in this question is
.. Therefore:
.
.
Answer:
hardest
Explanation:
Diamonds are known as the hardest naturally occurring substance known.
Answer:
Protons, Electrons, and neutrons
Answer:
V = 49.05 [m/s]
Explanation:
We can easily find the result using kinematics equations, first, we will find the distance traveled during the 5 seconds.

where:
Yo = initial position = 0
y = final position [m]
Vo = initial velocity = 0
t = time = 5 [s]
g = gravity aceleration = 9.81 [m/s^2]
The initial speed is zero, as the body drops without imparting an initial speed. Therefore:
y = 0 + (0*5) + (0.5*9.81*5^2)
y = 122.625[m]
Now using the following equation we can find the speed it reaches during the 5 seconds.
![v_{f} ^{2}= v_{i} ^{2}+(2*g*y)\\v_{f}=\sqrt{2*9.81*122.625} \\v_{f}=49.05 [m/s]](https://tex.z-dn.net/?f=v_%7Bf%7D%20%5E%7B2%7D%3D%20v_%7Bi%7D%20%5E%7B2%7D%2B%282%2Ag%2Ay%29%5C%5Cv_%7Bf%7D%3D%5Csqrt%7B2%2A9.81%2A122.625%7D%20%5C%5Cv_%7Bf%7D%3D49.05%20%5Bm%2Fs%5D)