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3 years ago

Define the term “force”.

Physics

2 answers:

romanna [79]3 years ago

6 0

The Jedi have the force. it flows through all things. Joking it will change the motion of an object

Aleonysh [2.5K]3 years ago

3 0

Energy that is applied to an object.

--TheOneandOnly003

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Describe the shape of a convex lens and explain what it does to light.

alexira [117]

Convex lenses are thicker at the centers than the edges, they are known as the converging lenses. Rays of light that pass through the lens are brought closer together (they converge). When rays of light that are parallel pass through a convex lens they are refracted, the refracted rays converge at one point called the principal focus.

4 0

3 years ago

Explain the role of gravity and inertia in keeping the moon in orbit? 15points pleaseee

lidiya [134]

Answer:

gravity from the earth pulls the moon and the momentum of the rotaion and orbit of the moon keeps it moving

Explanation:

6 0

4 years ago

A man stands on the roof of a building of height 17.0 m and throws a rock with a velocity of magnitude 33.0 m/s at an angle of 3

arlik [135]

Answer:

(A). The maximum height above the roof reached by the rock is 16.48 m.

(B). The velocity of the rock before hitting the ground is 37.6 m/s.

(C). The horizontal distance from the base of the building to the point where the rock strikes the ground is 122.7 m.

Explanation:

Given that,

Height = 17.0 m

Velocity = 33.0 m/s

Angle = 33.0°

(A). We need to calculate the maximum height above the roof reached by the rock

Using formula of height

$h=\dfrac{v^2}{2g}$

$h=\dfrac{(v_{0}\sin\theta)^2}{2g}$

Put the value into the formula

$h=\dfrac{(33\times\sin33)^2}{2\times9.8}$

$h=16.48\ m$

(B). We need to calculate the time

Using equation of motion

$-h=v_{y}t-\dfrac{1}{2}gt^2$

Put the value into the formula

$-17.0=(v_{0}\sin\theta)t-4.9t^2$

$-17.0=(33.0\times\sin33)t-4.9t^2$

$4.9t^2-17.9t-17.0$

$t = 4.435\ sec$

We need to calculate the magnitude of the velocity of the rock just before it strikes the ground

Using equation of motion

$v_{y}=v_{0}\sin\theta-gt$

$v_{y}=(33.0\times\sin33)-9.8\times4.435$

$v_{y}=-25.48\ m/s$

The velocity of the rock before hitting the ground is

$v=\sqrt{v_{x}^2+v_{y}^2}$

$v=\sqrt{(v_{0}\cos\theta)^2+v_{y}^2}$

$v=\sqrt{(33\cos33)^2+(-25.48)^2}$

$v=37.6\ m/s$

(C). We need to calculate the horizontal distance from the base of the building to the point where the rock strikes the ground

Using equation of motion

$R=v_{x}\times t$

$R=v_{0}\cos\theta\times t$

Put the value into the formula

$R=33\times\cos33\times4.435$

$R=122.7\ m$

Hence, (A). The maximum height above the roof reached by the rock is 16.48 m.

(B). The velocity of the rock before hitting the ground is 37.6 m/s.

(C). The horizontal distance from the base of the building to the point where the rock strikes the ground is 122.7 m.

4 0

4 years ago

The human nervous system can propagate nerve impulses at about 102 m>s. Estimate the time it takes for a nerve impulse to tra

Olin [163]

Answer:

t = 0.196 s

Explanation:

The speed of a pulse is determined by the characteristics of the medium, its density and its resistance to stress, as long as these remain the speed will be constant for which we can use the kinetic expressions of the uniform movement

v = x / t

t = x / v

calculate

t = 2/102

t = 0.196 s

4 0

3 years ago

( Can someone help? )

Murrr4er [49]

Answer:

Answer would be 0.33

Explanation:

Calculations

8 0

3 years ago

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