Answer:
You are asked to design a cylindrical steel rod 50.0 cm long, with a circular cross section, that will conduct 170.0 J/s from a furnace at 350.0 ∘C to a container of boiling water under 1 atmosphere.
Explanation:
Given Values:
L = 50 cm = 0.5 m
H = 170 j/s
To find the diameter of the rod, we have to find the area of the rod using the following formula.
Here Tc = 100.0° C
k = 50.2
H = k × A × ![\frac{[T_{H -}T_{C} ] }{L}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BT_%7BH%20-%7DT_%7BC%7D%20%5D%20%7D%7BL%7D)
Solving for A
A = ![\frac{H * L }{k * [ T_{H}- T_{C} ] }](https://tex.z-dn.net/?f=%5Cfrac%7BH%20%2A%20L%20%7D%7Bk%20%2A%20%5B%20T_%7BH%7D-%20T_%7BC%7D%20%5D%20%7D)
A = ![\frac{170 * 0.5}{50.2 * [ 350 - 100 ]}](https://tex.z-dn.net/?f=%5Cfrac%7B170%20%2A%200.5%7D%7B50.2%20%2A%20%5B%20350%20-%20100%20%5D%7D)
A =
= 6.77 ×
m²
Now Area of cylinder is :
A =
d²
solving for d:
d = 
d = 9.28 cm
1 Watt = 1 joule/second
650 watts = 650 joules/second
(650 J/sec) x (3,600 seconds/1 hour) = <em>2,340,000 Joules/hour</em>
The maximum speed of Tim is 16.95 m/s.
The given parameters:
- Mass of the rope, m = 71 kg
- Tension on the rope, T = 220 N
- Coefficient of kinetic friction, = 0.1
- Time of motion, t = 8 s
<h3>What is Newton's second law of motion?</h3>
- Newton's second law of motion states that, the force applied to an object is directly proportional to the product of mass and acceleration of the object.
The net force on Tim is calculated by applying Newton's second law of motion as follows;

Thus, the maximum speed of Tim is 16.95 m/s.
Learn more about net horizontal force here: brainly.com/question/21684583
Answer:
A. not excludable and not rival in consumption.
Explanation: