Side BC is congruent to side BC.
Using the congruent angles and the angle bisectors, you can get two angles congruent to two other angles, so you use ASA to prove the triangles congruent. Then you use CPCTC to prove the sides congruent.
Answer: C.) ASA
R^2/2(pi/180*D-sin(D)) is the formula so 6^2/2(pi/180*120-sin(120)) is the problem which comes to about 22cm^2
X-7=18
+7 to both side
X=25
Answer:
Theta = 59 degrees
Step-by-step explanation:
Here, we want to get the value of the marked angle
To do this, we use the appropriate trigonometric ratio
From what we have,
The side 42 ft is adjacent the angle given
The side facing the right angle is 82 ft
The trigonometric ratio that connects the adjacent and the hypotenuse is cosine. It is the ratio of the adjacent to the hypotenuse
Cos theta = 42/82
theta = cos^-1 0.5122
theta= 59.189
To the nearest degrees, this is 59 degrees
Answer:
The endpoints of the line segment CD are:
$$C=(x_1,y_1)= (-4, 8) \\ D= (x_2,y_2)= (8, -4) $$
We find the midpoint using th
