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lara31 [8.8K]
2 years ago
3

3. Give two reasons why there are different values for the weighted average atomic mass of Candium

Chemistry
1 answer:
fiasKO [112]2 years ago
6 0

The majority of elements are found in mixtures of two or more isotopes in nature. Every element's isotope has a set mass and a natural percent abundance. These isotopes' masses in their respective abundances must be reflected in the element's mass.

  • Every isotope contributes to the average atomic mass of an element, which is displayed in the element's box on most periodic tables (at least, the isotopes that exist naturally). However, the average is a weighted average.
  • A weighted average mass is an average that considers the frequency of each mass in the sample.
  • Atoms with the same atomic number that have varied masses because of differing neutron counts are known as isotopes. The weighted average of an element's isotopes' masses determines its atomic mass. Each isotope's mass and relative abundance as they exist in nature are considered in the weighted average.

These are the reasons for different values of weighted average atomic mass.

Learn more about atomic mass:

brainly.com/question/26299782

#SPJ9

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oxygen is a common oxidizing agent in nature. what change in the oxidation number of oxygen must occur if it is to be an oxidizi
Minchanka [31]

Answer is: the oxidation number of oxygen must decrease.

Oxidizing agent is element (substance) that gain electrons in chemical reaction.

For example, balanced chemical reaction: C + O₂ → CO₂.

Oxygen change oxidation number from 0 to oxidation number -2 (reduction) and carbon change from 0 to +4 (oxidation)

6 0
3 years ago
Given that NASA needs 151,200 g of Oxygen (O2) per person for a mission, how many grams of water (H2O) does NASA need to ship to
IgorC [24]

this is so ez,

ok so here what u'll do after u balance the equation:

1. convert grams of oxygen to moles of oxygen.

2. convert moles of oxygen to moles of water

3. convert moles of water to grams of water.

4. bOOm... that's your answer

as follows:

2H2O(l)===>2H2(g)+O2(g)

1. 151200(g)/16(g/mol)=9540 moles of O2

2. 9450 moles of O2 × 2 moles of H2O =18900 moles of H2O

3. 18900 moles of H2O × 10g/mol = 189000g of H2O is required.

6 0
4 years ago
There is a gas at 780 mm of Hg, in a volume of 5 liters and a temperature of 37 ​ C, the volume is changed to 5.5 liters and the
HACTEHA [7]

Answer:

32.8 C

Explanation:

- Use combined gas law formula and rearrange.

- Hope that helped! Please let me know if you need further explanation.

6 0
4 years ago
Draw all resonance structures for the nitryl fluoride molecule, no2f.
denis-greek [22]
From  electronic  configuration valence electron of  Nitrogen is 5,  oxygen  6x2  which 12 since it  involve  two  molecules ,  that of is frulorine is  7, and  that No2F is 24  which  is  gotten  form  adding (5,12,7  ).All  resonance structure  are  as  follows
       F
 ..    I    ..
: O : N :O: 
 
              ..
     OR  : F:
              I                             

             N                                                  ..                                                                                                                                    : F:

          /         \                        or                   I

   ..                 ..                                               N

:O  :            :O:                                       / /        \\
                                                            / /               \\
                                                         :O :            :  O:
7 0
4 years ago
A balanced chemical equation is a direct presentation of the ___________.
Lisa [10]

Answer:

The chemical equation needs to be balanced so that it follows the law of conservation of mass. A balanced chemical equation occurs when the number of the different atoms of elements in the reactants side is equal to that of the products side.

Explanation:

How do you balance equations?

In general, however, you should follow these steps:

1. Count each type of atom in reactants and products.

2. Place coefficients, as needed, in front of the symbols or formulas to increase the number of atoms or molecules of the substances.

3. Repeat steps 1 and 2 until the equation is balanced.

5 0
3 years ago
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