Answer:
[PCl₃] = 0.031M
[Cl₂] = 0.031M
[PCl₅] = 0.969M
Explanation:
Based on the reaction:
PCl₅(g) ⇄ PCl₃(g) + Cl₂(g)
<em>Where Keq = 1.0x10⁻³ = [PCl₃] [Cl₂] / [PCl₅]</em>
Inital [PCl₅] = 2.0mol / 2.0L = 1M.
In equilibrium:
[PCl₃] = X
[Cl₂] = X
[PCl₅] = 1M-X
<em>Where X is reaction coordinate</em>
<em />
Replacing:
1.0x10⁻³ = [X] [X] / [1-X]
1.0x10⁻³ - 1.0x10⁻³X = X²
1.0x10⁻³ - 1.0x10⁻³X - X² = 0
Solving for X:
X = -0.032M. False solution, there is no negative concentration
X = 0.031M
That means equlibrium concentrations are:
[PCl₃] = 0.031M
[Cl₂] = 0.031M
[PCl₅] = 1-0.031M = 0.969M
<h3>[PCl₃] = 0.031M</h3><h3>[Cl₂] = 0.031M</h3><h3>[PCl₅] = 0.969M</h3>
Answer:
A.) Q < K because Q decreased
B. shift right
Explanation:
Reactant-------->Products
K = Product/Reactant
An endothermic reffers to any reaction which absorbs energy from its surroundings, usually in the form of heat.
ΔH. In endothermic reactions, K increases when Temperature increases.
The given reaction is an endothermic reaction, and in an endothermic reaction, when there is increase in temperature, the product side is more favored. The system will shifts to the right side of the reaction. Q < K then K is constant and Q is decreased.then Q < K because Q decreased
The system respond to a temperature increase by shifting to the right
atomic mass of magnesium = 24.305
atomic mass of chlorine = 35.453
molecular mass of MgCl2 = 24.305+2*35.453 = 95.211
Number of moles in 338 g of pure MgCl2
= 338/95.211 = 3.55001 moles
Ans. there are 3.55 moles of MgCl2 in 338 g of the substance.