The question is incomplete, the complete question is;
Arrange the isotopes of chlorine and sulfur in order of decreasing number of neutrons. Rank the isotopes from most to fewest neutrons. To rank items as equivalent S-33,S-36,S-34,Cl-35,S-32,Cl-37
The isotopes of sulphur arranged in order of decreasing number of neutrons is; S-36, S-34, S-33, S-32. The isotopes of chlorine arranged in order of decreasing number of neutrons is; Cl-37, Cl-35.
Isotopes are atoms of the same element having different mass numbers but the same atomic number.
Isotopes differ in their number of neutrons. The number of neutrons is obtained by subtracting the atomic number of an isotope from its mass number.
The number of neutrons in the isotopes of sulphur are;
S-36 (20 neutrons)
S-34 (18 neutrons)
S-33 (17 neutrons)
S-32 (16 neutrons)
The number of neutrons in the isotopes of chlorine are;
Cl-37 (20 neutrons)
Cl-35 (18 neutrons)
Learn more: brainly.com/question/13214440
Answer:
2.498g
Explanation:
First off it's important to know Avogadro's number relationship with number of moles and molar mass.
It is given as;
1 mole = 6.02 * 10^23 atoms.
A mole's weight is equal to it's molar mass. Hence the equation can be changed to;
1 mole = molar mass = 6.02 * 10^23 atoms
In this problem, molar mass of Sulphur is 32g/mol. This means 1 mole of sulphur weighs 32 g and contains 6.02 * 10^23 atoms. What mass of sulphur would then contain 4.7x10^22 of atoms?
This leads us to;
32 g = 6.02 * 10^23
x g = 4.7x10^22
Upon cross multiplication, we have;
x = (4.7x10^22 * 32) / 6.02 * 10^23
x = 24.98 * 10^-1
x = 2.498g
M = 81.50g, mm = m/n
n = ???
PV = nRT --> n = PV/RT
n = (1.75)(4.92)/(.0821)(307)
n = 8.61/25.20 = .342
--> mm = m/n = 81.5/.342 = 238.58
1. to calculate molar mass , you need average atomic mass of each element.
formula is simple
suppose we have Na2CO3
here it says
there are
2 atoms of Na
1 atom of C
3 atom of O
now
molar mass = (total atoms of Na × average atomic mass of Na) + ( total atom of C × average atomic mass of C )+ (total atom of O × average atomic mass of O)
i hope you can figure out it now.
in case of (NH4)2
this means you have 2 count of NH4
so total atoms of N = 2
total atoms of H = 4×2 = 8
so on you can now figure it out
2. balanced equation
here LHS and RHS shoild have same number of atoms of each element .
for example
H2 + Cl2 => 2HCl
here 2 atoms of H combined with 2 atoms of Cl , we know H and Cl combined and formed HCl now because total H atoms are 2 and Cl atoms are 2 in LHS then we should also have 2 atoms of each in right side
so thats why we have 2HCl in right side.
Try to figure out . let me know if need any help
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