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ELEN [110]
1 year ago
9

X/6 + 4 = 15 what does x equal? What is x?

Mathematics
2 answers:
astraxan [27]1 year ago
8 0

Answer:

x=66

Step-by-step explanation:

x/6 +4=15

or, x+24/6=15

or,x+24=90

or,x=90-24

Hence, x=66

Umnica [9.8K]1 year ago
4 0
Hello there! x = 66.

x/6 + 4 = 15

This means that since 15 - 4 = 11, x/6 = 11.

Given the two numbers and a variable, we can multiply:

6 x 11 = 66

66/6 = 11

Therefore, x = 66

Hope this helps!
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What is the square root of 248 + square root of 63​
enyata [817]

Answer:

1) √248 = ± 15.7480157

2)√63 = ± 7.93725393

 

Step-by-step explanation:

7 0
3 years ago
Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S. In other words, find the flux of
tresset_1 [31]

Because I've gone ahead with trying to parameterize S directly and learned the hard way that the resulting integral is large and annoying to work with, I'll propose a less direct approach.

Rather than compute the surface integral over S straight away, let's close off the hemisphere with the disk D of radius 9 centered at the origin and coincident with the plane y=0. Then by the divergence theorem, since the region S\cup D is closed, we have

\displaystyle\iint_{S\cup D}\vec F\cdot\mathrm d\vec S=\iiint_R(\nabla\cdot\vec F)\,\mathrm dV

where R is the interior of S\cup D. \vec F has divergence

\nabla\cdot\vec F(x,y,z)=\dfrac{\partial(xz)}{\partial x}+\dfrac{\partial(x)}{\partial y}+\dfrac{\partial(y)}{\partial z}=z

so the flux over the closed region is

\displaystyle\iiint_Rz\,\mathrm dV=\int_0^\pi\int_0^\pi\int_0^9\rho^3\cos\varphi\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi=0

The total flux over the closed surface is equal to the flux over its component surfaces, so we have

\displaystyle\iint_{S\cup D}\vec F\cdot\mathrm d\vec S=\iint_S\vec F\cdot\mathrm d\vec S+\iint_D\vec F\cdot\mathrm d\vec S=0

\implies\boxed{\displaystyle\iint_S\vec F\cdot\mathrm d\vec S=-\iint_D\vec F\cdot\mathrm d\vec S}

Parameterize D by

\vec s(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec k

with 0\le u\le9 and 0\le v\le2\pi. Take the normal vector to D to be

\vec s_u\times\vec s_v=-u\,\vec\jmath

Then the flux of \vec F across S is

\displaystyle\iint_D\vec F\cdot\mathrm d\vec S=\int_0^{2\pi}\int_0^9\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec s_u\times\vec s_v)\,\mathrm du\,\mathrm dv

=\displaystyle\int_0^{2\pi}\int_0^9(u^2\cos v\sin v\,\vec\imath+u\cos v\,\vec\jmath)\cdot(-u\,\vec\jmath)\,\mathrm du\,\mathrm dv

=\displaystyle-\int_0^{2\pi}\int_0^9u^2\cos v\,\mathrm du\,\mathrm dv=0

\implies\displaystyle\iint_S\vec F\cdot\mathrm d\vec S=\boxed{0}

8 0
3 years ago
Assume y varies directly with x. when y=2 2/3 when x=1/4, what is y when x=1 1/8? NEED HELP QUICK!!
snow_tiger [21]

3y=8x

Explanation:

If y varies directly with x then

y=c⋅x for some constant of variation c

If (x,y)=(14,23) is a solution to this equation, then

23=c⋅14

→c=23⋅41=83

So

y=83x

or (clearing the fraction)

3y=8x

7 0
3 years ago
Can someone help me with this please !!
pogonyaev

add all amd divide by the 40 ???let me know if im wrong

7 0
3 years ago
Read 2 more answers
Please help! first person gets brainliest!
White raven [17]

Answer:

simple event and dependent event

Step-by-step explanation:

not needed

6 0
3 years ago
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