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1 year ago

Muscles break down glucose into lactate which undergoes glycolysis. the end product of glycolysis in active muscles is:_______

Biology

1 answer:

Doss [256]1 year ago

8 0

The end product of glycolysis in active muscles is lactate.

<h3>What is glycolysis?</h3>

The metabolic process known as glycolysis turns the sugar glucose (C6H12O6) into pyruvate (CH3COCO2H).
The high-energy molecules adenosine triphosphate (ATP) and reduced nicotinamide adenine dinucleotide (NADH) are created using the free energy released during this process.
A series of ten enzyme-catalyzed processes make up glycolysis, binding energy of carbs is captured.
Glucose is converted by muscles into lactate, which passes through glycolysis.
Lactate is the byproduct of glycolysis in working muscles.

To learn more about glycolysis visit:

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Explanation:

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This pathway is somewhat the reverse of the glycolysis when excess energy is present as a result of glycolysis, gluconeogenesis is inhibited and when no energy is present, gluconeogenesis is activated.

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3 years ago

Una solución de 0.204 M de NaOH seutiliza para neutralizar 50 mL de una solución de H3PO4. Si se necesitaron 16.4 mL de la soluc

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Explanation:

Para responder esta pregunta, hay que tener en cuenta la Ley de Conservación de la Masa. <u>La misma indica que en una reacción química en un sistema cerrado, la masa total de las moléculas que participan permanece constante.</u> Esto significa que la masa utilizada en los reactivos es la misma que la masa de los productos generados.

En este problema, se cuenta con una solución de NaOH (hidróxido de sodio) tiene una molaridad de 0.204 (siendo la molaridad el número de moles por litro de solución) y se utilizan 16.4 mL de dicha solución para agregarla a 50 mL de una solución de H3PO4 (ácido fosfórico).

Entonces, ya que la masa de ambas soluciones no se pierde, podemos utilizar la ecuación de la Ley de Conservación de la Masa:

Concentración inicial x Volumen inicial = Concentración final x Volumen final.

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Volumen inicial: 16.4 mL

Concentración final: ?

Volumen final: 50 mL + 16.4 mL = 66.4 mL

Reemplazamos los valores en la ecuación:

0.204 M x 16.4 mL = Concentración final x 66.4 mL

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