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pshichka [43]
2 years ago
15

Simplify 7x²+3x-5x²-10x

Mathematics
1 answer:
solmaris [256]2 years ago
3 0

Answer:

2x²-7x

Step-by-step explanation:

7x²-5x²=2x²

10x-3x=7x

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A bag contains 8 red balls and 4 white balls. Two balls are drawn without replacement. (Enter your probabilities as fractions.)
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Answer:

total marbles;12

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probabilities are 4/11

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2 years ago
What’s the answer to 10,11,12, and 13
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sorry misread the question

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1 year ago
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Brainers, please help me out. Thanks
quester [9]

The Pythagorean Theorem is a^2 + b^2 = c^2 where a and b are the sides and c is the hypotenuse.

From the picture you have a = 10 and c = 15.

Now you have:

10^2 + b^2 = 15^2

Simplify:

100 + b^2 = 225

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6 0
3 years ago
Kito makes on online purchase of a guitar case for $39.99, a tuner for $24.99 and picks for $26.99. Taxes are 6% of the total pu
maria [59]

Answer:

a. Kito has been billed correctly

Step-by-step explanation:

We simply need to check Kito's work to see if his price is accurate.

First, we can add the prices together to find the price before the sales tax is applied:  39.99 + 24.99 + 26.99 = $91.97

We can use this formula to figure out the total cost, C, after the sales tax, t is added:

C = l + (l * (t / 100)), where l = the price before applying the sales tax

C = 91.97 + (91.97 * (6 / 100)) = 97.4882 = $97.49

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If we did not round before, we would still get the same answer when rounding:  97.4882 + 8.20 = 105.6882 = $105.69

4 0
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Look at the image. (calculus)
mash [69]
<h3>Answer: Choice H)  2</h3>

=============================================

Explanation:

Recall that the pythagorean trig identity is \sin^2 x + \cos^2x = 1

If we were to isolate sine, then,

\sin^2 x + \cos^2x = 1\\\\\sin^2 x = 1-\cos^2x\\\\\sin x = \sqrt{1-\cos^2x}\\\\

We don't have to worry about the plus minus because sine is positive when 0 < x < pi/2.

Through similar calculations, \cos x = \sqrt{1-\sin^2x}\\\\

Cosine is also positive in this quadrant.

-------------

So,

\frac{\sqrt{1-\cos^2x}}{\sin x}+\frac{\sqrt{1-\sin^2x}}{\cos x}\\\\\frac{\sin x}{\sin x}+\frac{\cos x}{\cos x}\\\\1+1\\\\2

Therefore,

\frac{\sqrt{1-\cos^2x}}{\sin x}+\frac{\sqrt{1-\sin^2x}}{\cos x}=2

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5 0
2 years ago
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