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Elis [28]
2 years ago
12

What is toms score please?

Mathematics
2 answers:
Andrews [41]2 years ago
4 0

Answer: The answers is 47.5

Step-by-step explanation: What you do is this you take 50-5/2=47.5

ICE Princess25 [194]2 years ago
3 0

Answer:

125

Step-by-step explanation:

5 / 2     *  50

5/2  * 50/1

(5*50) / (2*1)

250 / 2   = 125

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The altitude of Object B is 27 times the altitude of Object A. The altitude of Object A is $3^3$ feet. What is the altitude of O
Andrej [43]

Answer:

3^6

Step-by-step explanation:

We know that A is 3^3 and B is 27 times that.

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3 years ago
A man 2 m high observes the angle of elevation to the top of a building to be 71° and the angle of depression to the bottom of t
Yuki888 [10]

Answer:

The building is 13.91 m tall

Step-by-step explanation:

The parameters given are;

Angle of elevation to the top of the building = 71°

Angle of depression to the bottom of the building = 26°

Height of the man = 2  m

Therefore, the sight of the man, the man's height, and the distance of the man from the building forms a triangle where:

The hypotenuse side = The sight of the man to the bottom of the building

Hence;

In ΔABC, A being at the eye level or head level of the man, B at the foot and C at the bottom of the building

∴ ∠A + Angle of depression to the bottom of the building = 90°

∠A = 90° - 26° = 64°

∠B = 90° and ∠C = 26° (Sum of angles in a triangle)

Tan(C) = \frac{AB}{BC}

Distance of the man from the building = BC

Tan(26) = \frac{2}{BC}

BC= \frac{2}{ Tan(26) } = 4.1 \, m

Given that the angle of elevation to the top of the building = 71°, we have;

ΔAET

Where:

A is at the head level of the man,

E is the point on the building directing facing the man and

T is the top of the building

Hence AE = BC and ∡TAE = 71°

TE + AB= The height of the building

Tan(TAE) = \dfrac{TE}{AE}\\\\Tan(71) = \dfrac{TE}{4.1}

∴ TE = tan(71°) × 4.1 = 11.91 m

Hence the height of the building = 11.91 + 2 = 13.91 m.

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3 years ago
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Deffense [45]
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