<u>Answer:</u> The volume of barium hydroxide is 183 mL.
<u>Explanation:</u>
To calculate the moles of cadmium nitrate, we use the equation:
.....(1)
Molarity of = 0.796 M
Volume of = 161 mL = 0.161 L (Conversion factor: 1 L = 1000 mL)
Putting values in equation 1, we get:
The chemical equation for the reaction of manganese sulfate and barium hydroxide follows:
By Stoichiometry of the reaction:
1 mole of manganese sulfate reacts with 1 mole of barium hydroxide.
So, 0.13 moles of manganese sulfate will react with = of barium hydroxide
Now, calculating the volume of barium hydroxide by using equation 1, we get:
Moles of barium hydroxide = 0.13 moles
Molarity of barium hydroxide = 0.710 M
Putting values in equation 1, we get:
Converting this into milliliters, we use the conversion factor:
1 L = 1000 mL
So,
Hence, the volume of barium hydroxide is 183 mL.