Answer would be neither!
The reason being that it can take the shape and volume of anything.
I don’t know jsnshanhs shznjs
Northern atlantic and northern pacific oceans
Answer:
0.04 M is the lowest concentration of chloride ions that would be needed to begin precipitation.
Explanation:
Concentration of lead nitarte = ![[Pb(NO_3)_2]=0.010 M](https://tex.z-dn.net/?f=%5BPb%28NO_3%29_2%5D%3D0.010%20M)

1 Mole of lead nirate gives 1 mole of lead ion.
Concentration of lead ion in the solution = 

Concentration of chloride ions = ![[Cl^-]](https://tex.z-dn.net/?f=%5BCl%5E-%5D)
The value of ![K_{sp} for [tex]PbCl_2= 1.6\times 10^{-5}](https://tex.z-dn.net/?f=K_%7Bsp%7D%20for%20%5Btex%5DPbCl_2%3D%201.6%5Ctimes%2010%5E%7B-5%7D)
![K_{sp}=[Pb^{2+}][Cl^{-}]^2](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BPb%5E%7B2%2B%7D%5D%5BCl%5E%7B-%7D%5D%5E2)
![1.6\times 10^{-5}=0.010 M\times [Cl^{-}]^2](https://tex.z-dn.net/?f=1.6%5Ctimes%2010%5E%7B-5%7D%3D0.010%20M%5Ctimes%20%5BCl%5E%7B-%7D%5D%5E2)
![[Cl^-]=0.04 M](https://tex.z-dn.net/?f=%5BCl%5E-%5D%3D0.04%20M)
0.04 M is the lowest concentration of chloride ions that would be needed to begin precipitation.
Answer:
0.533 mol O2
Explanation:
4 Fe3O4 + O2 -> 6 Fe2O3
1 mol O2 -> 6 mol Fe2O3
x -> 3.2 mol Fe2O3
x = (3.2 mol Fe2O3 * 1 mol O2)/ 6 mol Fe2O3
x= 0.533 mol O2