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postnew [5]
3 years ago
9

A gardener has 920 feet of fencing to fence in a rectangular garden. One side of the garden is bordered by a river and so it doe

s not need any fencing. garden bordered by a river Opens externally What dimensions would guarantee that the garden has the greatest possible area? shorter side: 0 Incorrect ft (feet) longer side: 920 Incorrect ft (feet) greatest possible area: 0 Incorrect ft2 (square-feet)
Mathematics
1 answer:
yuradex [85]3 years ago
3 0

Answer:

splitting it evenly among all three sides gives us the greatest area. ( for example if we had to split the number 10 into 2 and find the greatest area, out of all possible ways 5*5 is the greatest). Two sides have to be equal since it's a rectangle.

918/3=306

So we can make the two equal sides 306, and the longer side 308 which makes sure that we have the greatest area.

306 * 308

Step-by-step explanation:

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Answer:

(c) 2

Step-by-step explanation:

2(x - 4) + 7 = 3

2x + 2(-4) + 7 = 3

2x - 8 + 7 = 3

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2x - 1 + 1 = 3 + 1

2x = 4

2x/2 = 4/2

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Hope this helps!!!

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Using algebra, solve the inequality<br> writing your answer in set notation.<br> x²-x&gt; 20
Xelga [282]

Answer:

(-4, 0) U (1, ∞)

Step-by-step explanation:

Set each factor EQUAL to zero to find the zeroes (since it is not actually equal to zero, you will use an open circle when graphing and an open bracket when writing in interval notation).

x = 0           x-1 = 0             x + 4 = 0

                  x = 1                x = -4

Next, choose a value to the far left, between each of the zeroes, and to the far right to evaluate if it makes a true statement when input into the given inequality.

far left (I choose -5): -5(-5 - 1)(-5 + 4) > 0   →  (-)(-)(-) > 0  →   negative > 0  FALSE

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3 0
1 year ago
hi I was just a little bit of time with my module and I didn't know what is answer of the module now please please be sure of th
GREYUIT [131]

1. 5 x 4 = A. 20

2.

\frac{2}{5}  \times 25 = 2 \times 5 = 10

the answer is D. 25

3.

\frac{3}{5}  \div 15 =  \frac{3}{5}  \times  \frac{1}{15}  =  \frac{1}{5}  \times  \frac{1}{5}  =  \frac{1}{25}

the answer is A. 1/25

4.

4 \div  \frac{1}{2}  = 4 \times  \frac{2}{1}  = 8

the answer is C. 8

5.

9 \div  \frac{1}{3}  = 9 \times  \frac{3}{1}  = 27

the answer is D. 27

6.

20 \div  \frac{1}{4}  = 20 \times  \frac{4}{1}  = 80

the answer is D. 80

7.

\frac{9}{10}  \div  \frac{1}{2}  =  \frac{9}{10}  \times  \frac{2}{1}  =  \frac{18}{10}  =  \frac{9}{5}  = 1 \frac{4}{5}

the answer is C. 1 4/5

8.

9 \div  \frac{3}{2}  = 9 \times  \frac{2}{3}  =  \frac{18}{ 3}  = 6

the answer is B. 6

9.

\frac{3}{4}  \div  \frac{3}{8}  =  \frac{3}{4}  \times  \frac{8}{3}  = 2

the answer is A. 2

3 0
2 years ago
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