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DIA [1.3K]
1 year ago
8

Find the value of x so that the shaded region is a gnomon to the white rectangle.

Mathematics
1 answer:
RUDIKE [14]1 year ago
4 0

Based on the shaded region, the value of x which makes this region a gnomon is x = 1.

<h3>What is value of x?</h3>

Based on the dimensions of the side that isn't shaded, and the dimensions of the side that is shaded, the value of x can be found as:

3/ 6 = (1 + 3) / (x + 6 + x)

1/2 =  4 / (6 + 2x)

6 + 2x = 4 / (1/2)

2x = 8 - 6

x = 2/2

x = 1

Find out more on shaded regions at brainly.com/question/9767762.

#SPJ4

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&gt;
kondor19780726 [428]

Answer:

23 degrees

Step-by-step explanation:

Find the diagram attached

The sum of angle on the straight line is 180°

103+3x+15+x+10 = 180

128+4x =180

4x = 180-128

4x = 52

x = 52/4

x = 13

The measure of the angle of the intersection between Derby Drive and Rosemont is x+10

= 13+10

= 23 degrees

Hence the measure of the angle is 23 degrees

5 0
3 years ago
If Point P is between Q and R and QP = 16 and Qr = 52. What is the length of PR?
Dimas [21]
1) Here, QR = QP + PR

52 = 16 + PR

PR = 52 - 16 = 36

In short, Your Answer would be Option C

2) Slope of mentioned line:
m = (5+5) / (0-4)
m = 10/-4
m = -5/2

Parallel lines have same slope so it would be -5/2 as well

In short, Your Answer would be Option B

Hope this helps!
5 0
3 years ago
X-y=5 and x+y=-10 is this parallel, perpendicular, or neither?
tiny-mole [99]

Answer:

Its perpendicular

Step-by-step explanation:

You can solve the equation to get x=-2.5 and y = -7.5 so they intersect there, but they intersect at 90 degrees so its perpendicular.

3 0
3 years ago
Does the number <img src="https://tex.z-dn.net/?f=%5Cfrac%7B284%7D%7B3%7D" id="TexFormula1" title="\frac{284}{3}" alt="\frac{284
Colt1911 [192]
Infinite , 94.66666666666667
4 0
3 years ago
Help ASAP
9966 [12]

Answer:

30.48 cm

Step-by-step explanation:

There are ~ 2.54 centimeters in 1 inch. If the ruler is 12 inches long, multiply 2.54 cm by 12:

12 inches x 2.54 cm = 30.48 cm.

5 0
3 years ago
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