- (A) The mainsail foot is 13 feet long, the luff is 10 feet long, the leach is 6.93 feet long, and the mainsail area is 64.85 ft².
- (B) The mainsail foot is 13 feet long, the luff is 10 feet long, and the luff forms a 50° angle with the leach at the head, requiring the length of the leach and the area of the mainsail.
<h3>
What exactly is sines law?</h3>
- The law of sines refers to the ratio of a triangle's side length to the sine of the opposite angle, which is the same for all sides.
- SinA/a = SinB/b = SinC/c
- Where A, B, and C represent the triangle's angle and a,b, and c represent the opposite sides of the triangle's angle.
So, Part A:
By employing the sines law,
- SinA/10 = SinB/13
- SinA/10 = Sin50/13
- A = 36.10
- C = 180-(180-36.10)
- C = 93.90
So,
- Sin36.10 / a = Sin50/ b = Sin93.90/c
- Sin36.10 / 10 = Sin50/ 13 = Sin93.90/c
- c = Sin93.90 × 13 ÷ Sin50
- c = 16.93 ft
Now, Part B:
Area of the mainsail:
- = 1/2 × abSinC
- = 1/2 × 10 × 13 × Sin93.90
- = 64.85
Therefore, the answers to both parts are:
- (A) The mainsail foot is 13 feet long, the luff is 10 feet long, the leach is 6.93 feet long, and the mainsail area is 64.85 ft².
- (B) The mainsail foot is 13 feet long, the luff is 10 feet long, and the luff forms a 50° angle with the leach at the head, requiring the length of the leach and the area of the mainsail.
Know more about sines law here:
brainly.com/question/27174058
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The complete question is given below:
A sailmaker is designing a mainsail for a newly constructed sailboat. The mainsail foot is 13 feet long, the luff is 10 feet long, and the luff makes a 50° angle at the head with the leach.
Part A: Determine the length of the leach.
Part B: Find the area of the mainsail.
PLS HELP :) 50 POINTS!!!
