This equation can be set up letting x be the hourly rate:40x+1.5x(52-40)=638 [40 times the rate, plus 1.5 times the rate for the hours over 40 equals the pay]40x+78x-60x=63858x=638x=11 hourly rate is $11/hr
Answer:
there are 14 possible outcomes
Step-by-step explanation:
this is because there are 14 marbles in the bag
Answer: D
Step-by-step explanation:
I am guessing but sorry if I am wrong
Answer:
13.
.
14. 
15. 2.
Step-by-step explanation:
13. 
= 
= 
= 
= 
= 
= 
=
.
14. 



.
15. ![\sqrt[3]{2} * \sqrt[3]{4}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2%7D%20%2A%20%5Csqrt%5B3%5D%7B4%7D)
= ![\sqrt[3]{2 * 4}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2%20%2A%204%7D)
= ![\sqrt[3]{2 * 2 * 2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2%20%2A%202%20%2A%202%7D)
= ![\sqrt[3]{2 ^3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2%20%5E3%7D)
= 2.
Hope this helps!
Answer:
The answer is below
Step-by-step explanation:
Let us assume the rate of printing in machine A is x per hour and the rate for machine B is y. Given that machine B prints at half the rate of machine A, therefore:
y = (1/2)x (1)
Also, both machine produces 200 newspaper printouts, and both operate at different times for a total of 4 hours. Therefore:
200/x + 200/y = 4 (2)
Put y = (1/2)x in equation:

Put x = 150 in equation y:
y=(1/2)150 = 75
Therefore the rate of machine A is 150 newspapers per hour while that of machine B is 75 newspapers per hour