The other isotope, given the data is 33% Z-211
<h3>Data obtained from the question</h3>
Ffrom the question given above, the following data were obtained:
- Average atomic mass = 208.99
- Mass of isotope A = 208 amu
- Abundance of A = 67%
- Abundance of B = 100 - 67 = 33%
- Mass of isotope B = ?
<h3>How to determine the other isotope</h3>
We can obtain the other isotope by calculating the mass. This can be obtain as illustrated below:
Average atomic mass = [(Mass of A × Abundance of A)/100] + [(Mass of B × Abundance of B)/100]
208.99 = [(208 × 67)/100] + [(Mass of B × 33)/100]
208.99 = 139.36 + (Mass of B × 0.33)
Collect like term
Mass of B × 0.33 = 208.99 - 139.36
Mass of B × 0.33 = 69.63
Divide both sides by 0.33
Mass of B = 69.63 / 0.33
Mass of B = 211
Thus, the other isotope is 33% Z-211
Learn more about isotope:
brainly.com/question/28223231
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