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3 years ago

Which is an example of a catalyst? heat stirring decrease in temperature

Chemistry

1 answer:

Lorico [155]3 years ago

3 0

I think the correct answer is decrease in temperature
I feel like that’s the right one

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what are the elements of the following compounds: sodium bromide,zinc sulphide,lead oxide,magnesium nitride,potassium oixide

Stella [2.4K]

Sodium , bromine zinc magnesium sulphur nitrogen potassium oxygen lead

4 0

3 years ago

What volume will be occupied by 33.0 grams of CO2 at 500 torr and 27 °C?

wlad13 [49]

Answer:

V = 27.98 L

Explanation:

Given data:

Mass of CO₂ = 33.0 g

Pressure = 500 torr

Temperature = 27°C

Volume occupied = ?

Solution:

Number of moles of CO₂:

Number of moles = mass/molar mass

Number of moles = 33.0 g/ 44 g/mol

Number of moles = 0.75 mol

Volume of CO₂:

PV = nRT

R = general gas constant = 0.0821 atm.L/ mol.K

Now we will convert the temperature.

27+273 = 300 K

Pressure = 500 /760 = 0.66 atm

By putting values,

0.66 atm×V = 0.75 mol × 0.0821 atm.L/ mol.K × 300 K

V = 18.47 atm.L/0.66 atm

V = 27.98 L

4 0

2 years ago

What is the mean free path for the molecules in an ideal gas when the pressure is 100 kPa and the temperature is 300 K given tha

sladkih [1.3K]

Answer:

The mean free path = 2.16*10^-6 m

Explanation:

Given:

Pressure of gas P = 100 kPa

Temperature T = 300 K

collision cross section, σ = 2.0*10^-20 m2

Boltzmann constant, k = 1.38*10^-23 J/K

To determine:

The mean free path, λ

Calculation:

The mean free path is related to the collision cross section by the following equation:

$\lambda =\frac{1}{n\sigma }------(1)$

where n = number density

$n = \frac{P}{kT}-----(2)$

Substituting for P, k and T in equation (2) gives:

$n = \frac{100,000 Pa}{1.38*10^{-23} J/K*300K} =2.42*10^{25}\ m^{3}$

Next, substituting for n and σ in equation (1) gives:

$\lambda =\frac{1}{2.42*10^{25}m^{-3}* .0*10^{-20}m^{2}}=2.1*10^{-6}m$

6 0

3 years ago

The force of attraction that the Earth exerts on all objects is called _____.

fomenos

The answer would be Gravity.

6 0

3 years ago

Read 2 more answers

Calculate the amount of heat energy required to heat up 21.5 grams of ice from -15 °C to 10°C.

Anuta_ua [19.1K]

Answer:

8.74kj

Explanation:

There are three steps

Warming up the ice to its melitng point. THe nergy required to melt it completely. The energy requiered to warm up the water to a certain temp.

It can be seen by the three equations written

5 0

2 years ago