Answer:
Br2(l) → BrO3-(aq) + Br-(aq)
A) Br2 = 3, OH - = 6
B) Br2 = 3, OH - = 3
C) Br2 = 2, OH - = 5
D) Br2 = 1, OH - = 2
E) Br2 = 1, OH - = 6
1. 12.992 L
2. 2.42 moles
3. 275.52 L
4. 567.844 g
<h3>Further explanation</h3>
Given
moles and volume at STP
Required
mass, volume and moles
Solution
Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters / mol.
1. 0.58 moles ammonia :
Volume = 0.58 moles x 22.4 L = 12.992 L
2. 77.5 grams of O₂ :
Moles = 77.5 grams x (1 mol/32 grams) = 2.42
3. 12.3 mole of Bromine gas :
Volume = 12.3 mole x (22.4 L/1 mole) = 275.52 L
4. 4.8 moles iron(II)chloride :
Mass = 4.48 moles x molar mass ( 126,751 g/mol) = 567.844 g
Evaporation is the rate at which liquid changes into gas. The higher the temperature the higher the increased rate of evaporation.
So if the liquid cools which means the temperature reduces, the rate of evaporation would decrease.
So evaporation rate decreases. B.
