The electrons and the nuclei will settle into positions that minimize repulsion and maximize attraction.
2. Rubidium
3. Antimony
4. Ytterbium
5. Einsteinium
Answer:
%N = 25.94%
%O = 74.06%
Explanation:
Step 1: Calculate the mass of nitrogen in 1 mole of N₂O₅
We will multiply the molar mass of N by the number of N atoms in the formula of N₂O₅.
m(N): 2 × 14.01 g = 28.02 g
Step 2: Calculate the mass of oxygen in 1 mole of N₂O₅
We will multiply the molar mass of O by the number of O atoms in the formula of N₂O₅.
m(O): 5 × 16.00 g = 80.00 g
Step 3: Calculate the mass of 1 mole of N₂O₅
We will sum the masses of N and O.
m(N₂O₅) = m(N) + m(O) = 28.02 g + 80.00 g = 108.02 g
Step 4: Calculate the percent composition of N₂O₅
We will use the following expression.
%Element = m(Element)/m(Compound) × 100%
%N = m(N)/m(N₂O₅) × 100% = 28.02 g/108.02 g × 100% = 25.94%
%O = m(O)/m(N₂O₅) × 100% = 80.00 g/108.02 g × 100% = 74.06%
Answer:
Yes because the law of conservation of matter is followed. There are equal numbers of atoms of all elements in the
reactants and products.
Explanation:
A balanced equation conform to the law of conservation of matter. While unbalanced equation suggests that matter has been created or destroyed.
Na3PO4 + 3KOH —> 3NaOH + K3PO4
A careful observation of the above equation proved that the equation is balanced is balanced because there are equal numbers of atoms of all elements in the
reactants and products.
