All categories

3 years ago

5 atoms Pb to mol Pb

Chemistry

1 answer:

jek_recluse [69]3 years ago

5 0

Answer:

0,83 x 10-²³ mol

Explanation:

n=N/Na

n=5:(6,02 x 10²³)

You might be interested in

How can a chemical reaction be sped up?Select from the drop-down menu to correctly complete the statement.

lara31 [8.8K]

Answer: Catalyst

Explanation: it speeds it up lol but basically the catalyst helps speed up the chemical reaction by reducing the activation energy or changing the reaction machenism/

8 0

3 years ago

Will the different flavors of khool aid effect the temperature of the boiling point

Andre45 [30]

No it does not effect the temperature of boiling point

8 0

3 years ago

12. What is the volume of 0.07 mol of neon gas at STP?

scoundrel [369]

<h3>Answer:</h3>

2 L Ne

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

Using Dimensional Analysis
STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K

<h3>Explanation:</h3>

<u>Step 1: Define</u>

0.07 mol Ne (g)

<u>Step 2: Identify Conversions</u>

STP - 22.4 L per mole

<u>Step 3: Convert</u>

Set up: $\displaystyle 0.07 \ mol \ Ne(\frac{22.4 \ L \ Ne}{1 \ mol \ Ne})$
Multiply: $\displaystyle 1.568 \ L \ Ne$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 1 sig fig.</em>

1.568 L Ne ≈ 2 L Ne

7 0

3 years ago

Hydrogen and nitrogen react to produce ammonia gas as shown in the following chemical

DerKrebs [107]

Explanation:

$31.5 \: g \: aommnia \: \times \: \frac{1 \: mol \: ammonia}{8 \: g \: ammonia \: } \: \times \frac{3 \: mol \: hydrogen}{2 \: mol \: ammonia} \: \times \frac{1 \: g \: hydrogen}{1 \: mol \: hydrogen} = \: 5.90625 \: g \: hydrogen \: must \: react \:$

5 0

3 years ago

A mixture of water and graphite is heated to 600 k in a 1 l container. when the system comes to equilibrium it contains 0.15 mol

Lunna [17]

(missing in Q) : Calculate the concentration of CO & H2 & H2O when the system returns the equilibrium???

when the reaction equation is:

C(s) + H2O(g) ↔ H2(g) + CO(g)

∴ Kc = [H2] [CO] / [H2O]

and we have Kc = 0.0393 (given missing in the question)

when the O2 is added so, the reaction will be:

2H2(g) + O2(g) → 2H2O(g)

that means that 0.15 mol H2 gives 0.15 mol of H2O

∴ by using ICE table:

[H2O] [H2] [CO]

initial 0.57 + 0.15 0 0.15

change -X +X +X

Equ (0.72-X) X (0.15+X)

by substitution:

0.0393 = X (0.15+X) / (0.72-X) by solving for X

∴ X = 0.098

∴[H2] = X = 0.098 M

∴[CO] = 0.15 + X

= 0.15 + 0.098 = 0.248 M

∴[H2O] = 0.72 - X

= 0.72 - 0.098

= 0.622 M

8 0

3 years ago