How many copper(I) ions (atoms of Cu 1+ ) are in a sample of copper(I) sulfate that weighs 35.4 grams?

What is the minimum (non-zero) thickness of a benzene (n = 1.501) thin film that will result in constructive interference when v

ad-work [718]

Explanation:

At each reflecting surface (benzene and glass) there will be 180 degree phase change.

Now, for constructive interference the optical path in benzene is $\lambda$ .

Formula to calculate thickness of a benzene thin film is as follows.

Optical path length through benzene ( $\lambda$ ) = $2 \times n \times d$

Hence, substituting the given values into the above formula as follows.

Optical path length through benzene = $2 \times n \times d$

d = $\frac{\text{Optical path length through benzene}}{2 \times n}$

= $\frac{\lambda}{2 \times n}$

= $\frac{615 \times 10^{-9}}{2 \times 1.501}$ (as 1 nm = $10^{-9}m$

= 204.9 m

Thus, we can conclude that minimum thickness of benzene is 204.9 m.

4 0

3 years ago

15.89 percent carbon, 21.18 percent oxygen, and 62.93 percent osmium. what is the empirical formula

otez555 [7]

Answer:

OsCO or COOs

Explanation:

Data given

Carbon = 15.89 %

Oxygen = 21.18 %

Osmium = 62.93%

Empirical formula = ?

Solution:

First find the masses of each component

Consider total compound is 100g

As we now

mass of element = % of component

So,

15.89 g of C = 15.89 % Carbon

21.18 g of O = 21.18 % Oxygen

62.93 g of Os = 62.93% Osmium

Now convert the masses to moles

For Carbon

Molar mass of C = 12 g/mol

no. of mole = mass in g / molar mass

Put value in above formula

no. of mole = 15.89 g/ 12 g/mol

no. of mole = 1.3242

mole of C = 1.3242

For Oxygen

Molar mass of O = 16 g/mol

no. of mole = mass in g / molar mass

Put value in above formula

no. of mole = 21.18 g/ 16 g/mol

no. of mole =

mole of O = 1.3238

For Os

Molar mass of Os = 190 g/mol

no. of mole = mass in g / molar mass

Put value in above formula

no. of mole = 62.93 g/ 190 g/mol

no. of mole =

mole of Os = 1.3312

Now we have values in moles as below

C = 1.3242

O = 1.3238

Os = 1.3312

Divide the all values on the smalest values to get whole number ratio

C = 1.3242 /1.3238 = 1.0003

O = 1.3238 /1.3238 = 1

Os = 1.3312 /1.3238 = 1.0056

So all have round value 1 mole

C = 1

O = 1

Os = 1

So the empirical formula will be (OsCO) i.e. all 3 atoms in simplest small ratio

7 0

3 years ago

What volume of 0.140 HCl is needed to neutralize 2.58 of Mg(OH)2<br> ? ...?

elena-s [515]

To make a first step you have to know the balanced form for neutralization formula: $Mg(OH)2(aq)+2HCl(aq)--\ \textgreater \ 2H2O+Mg(aq)+Cl(aq)
$
According to this, you can <span>calculate what you are being asked :</span> $0.0442molMg(OH)2(x)(2molHCl)/(1molMg(OH)2)=0.0885molHCl$
Then we have : $0.140MHCl=0.140(mol/L)HCl$
Hope everything is clear, here is the exact answer you need : $V=(0.0885molHCl)/(0.140(mol/L)HCl)=0.632LHCl
$

8 0

2 years ago

In the reaction between CO and Fe3O4, the theoretical yield in an experiment is calculated to be 47.2 g Fe. When a chemistry stu

dusya [7]

Answer:

C. 63.3%

Explanation:

Theoretical yield = 47.2g

Actual yield = 29.9g

Percentage yield = ?

The percentage yield of a compound after chemical synthesis is the ratio of the actual yield to the theoretical yield multiplied by 100.

Percentage yield = (actual yield / theoretical yield) × 100

Percentage yield = (29.9 / 47.2) × 100

Percentage yield = 0.6334 × 100

Percentage yield = 63.34%

The percentage yield of Fe is 63.34%

6 0

2 years ago

Read 2 more answers

The biomedical technique in which a part of the brain is destroyed with electric current is known as __________. A. electroconvu

FrozenT [24]

The Answer is C: Bilateral Cingulotomy

3 0

3 years ago

Read 2 more answers

How many copper(I) ions (atoms of Cu​ 1+ ) are in a sample of copper(I) sulfate that weighs 35.4 grams?

How many copper(I) ions (atoms of Cu 1+ ) are in a sample of copper(I) sulfate that weighs 35.4 grams?