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Alona [7]
1 year ago
5

What are the two main classes of simple machines?

Chemistry
2 answers:
Vlad [161]1 year ago
7 0

Answer:

Palanca.

Torno.

Polea.

Plano inclinado.

Cuña.

Tornillo.

Explanation:

Len [333]1 year ago
6 0
The lever family and the inclined plane family.
You might be interested in
An alkene X undergoes ozonolysis and gives two compounds Y and Z of molecular formula CaHO. Y and Z are functional isomers of ea
lys-0071 [83]

i. The given compound X is 2-methyl pent-2-ene. When it is reacted with ozone it forms an ozonide in the first step. In the second step the reduce to forms acetone and propanal.

ii. The structural formula of Y is CH_3-CO-CH_3 and Z is CH_3-CH_2-CHO.

iii. Alkenes, upon catalytic hydrogenation, form alkanes. This will occur in the presence of Nickel as the catalyst.

iv. The process of ozonolysis is useful in the field of pharmaceutics.

v. The test of unsaturation can be performed by passing a compound through Bromine water.

<h3>What is ozonolysis?</h3>

Ozonolysis is a reaction used in organic chemistry to determine the position of a carbon-carbon double bond in unsaturated compounds.

i. The given alkene X, that is subject to ozonolysis would be 2-methyl-2-pentene. Upon exposure to ozone, an ozonide is initially formed, after which it is broken down into 2 products - acetone and propanal, both with the molecular formula C₃H₆O.

The given compound X is 2-methyl pent-2-ene. When it is reacted with ozone it forms an ozonide in the first step. In the second step the reduce to forms acetone and propanal.

ii. The formulas of Y is CH_3-CO-CH_3 and Z is CH_3-CH_2-CHO. They are functional isomers as they have the same molecular formula but different functional groups - ketone and aldehyde.

iii. When alkenes undergo catalytic hydrogenation, they form alkanes, X will form 2 methyl petane on reaction with hydrogen gas in presence of Ni.

iv. The ozonolysis is used for the industrial-scale synthesis of pharmaceuticals.

v. The unsaturation of compound X can be proved by the bromine water test. As on reaction with it, the brown colour of bromine water becomes colourless due to the formation of dibromo alkane.

Learn more about the ozonolysis here:

brainly.com/question/14356308

#SPJ1

5 0
2 years ago
Give the name of one of the 3 common acids used in chemistry
FrozenT [24]
I think one is Hydrochloric acid
7 0
2 years ago
Read 2 more answers
SOMEONE HELP WITH THAT THING PLSSS( I also didn’t know what to put as the topic)
rewona [7]

Answer:

hope this helps

Explanation:

Water was on earth with the dinosaurs and almost at the very start.

Water starts anywhere from clouds to ponds

I choose ponds, water evaporates from the sun and moves its way through the air being collected into clouds in the atmosphere, clouds are evaporated water molecules, then the water combines to form rain wich then end up on a hill and travel back to a water source or goes into the ground and makes groundwater and if there is enough rain overtime will form a pond.

6 0
3 years ago
Why amorphous solids are called super cooled liquids?
qwelly [4]
Because this classification contrasts with that of crystalline solids whose atoms are arranged in a regular and orderly fashion forming crystalline networks.
3 0
3 years ago
Which of these solutions is the most basic?
dalvyx [7]
<h2>Question↷</h2>

Which of these solutions is the most basic?

[OH-] = 4.3 x 10-9 M

[OH-] = 2.8 x 10-11 M

[OH-] = 6.7 x 10-10 M

[OH-] = 1.0 x 10-5 M

<h2>Answer↷</h2>

  • <u>[OH-] = 1.0 x 10-5 M</u> ✓

<h2>Solution↷</h2>

[OH-] = 4.3 x 10-9 M

  • [OH-] = 4.3 x 10^-9 M
  • pOH = - log [OH^1-]
  • pOH = - log [4.3 x 10^-9]
  • pOH = 8.36
  • pH = 14- 8.36
  • pH = 5.64

_______________________________________

[OH-] = 2.8 x 10-11 M

  • [OH-] = 2.8 x 10^-11 M
  • pOH = - log [OH^1-]
  • pOH = - log [2.8 x 10^-11 ]
  • pOH = 10.55
  • pH = 14-10.55
  • pH = 3.45

_______________________________________

[OH-] = 6.7 x 10-10 M

  • [OH-] = 6.7 x 10^-10 M
  • pOH = - log [OH^1-]
  • pOH = - log [6.7 x 10^-10]
  • pOH = 9.17
  • pH = 14-9.17
  • pH = 4.83

_______________________________________

[OH-] = 1.0 x 10-5 M

  • [OH-] = 1.0 x 10-5 M
  • pOH = - log [OH^1-]
  • pOH = - log [1.0 x 10^-5 ]
  • pOH = 5
  • pH = 14-5
  • pH = 9

_______________________________________

we know that , the solution with <u>pH > 7</u> is termed as basic and more the pH ,more the basicity, hence ,the solution with the highest pH would be the strongest base out of these all which is

<u>[OH-] = 1.0 x 10-5 M</u> with pH = 9

_______________________________________

4 0
2 years ago
Read 2 more answers
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