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dexar [7]
3 years ago
15

At a particular temperature, 12.0 moles of so3 is placed into a 3.0-l rigid container, and the so3 dissociates by the reaction 2

so3(g) 34 2so2(g) 1 o2(g) at equilibrium, 3.0 moles of so2 is present. calculate k for this reaction.
Chemistry
1 answer:
saul85 [17]3 years ago
4 0
            2 SO₃ --> 2 SO₂ + O₂
I             12             0          0
C           -2x           +2x      +x
---------------------------------------------
E         12-2x          2x         x

Since the moles of SO₂ at equilibrium is 3 mol, 2x = 3. Then, x = 1.5 mol. So, the amounts at equilibrium is:
SO₃: 12 - 2(1.5) = 9
SO₂: 2(1.5) = 3
O₂: 1.5

The formula for K basing on the stoichiometric reaction is:
K = [SO₂]²[O₂]/[SO₃]² 
where the unit used is conc in mol/L.

K = [3 mol/3 L]²[1.5 mol/3 L]/[9 mol/3 L]²
<em>K = 0.0556</em>
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a sample of an unknown gas has a mass of 0.582g. it's volume is 21.3 mL a a temp of 100 degrees Celsius and a pressure of 754 mm
Zielflug [23.3K]

Answer:

Molar mass = 0.09 × 10⁴ g/mol

Explanation:

Given data:

Mass = 0.582 g

Volume = 21.3 mL

Temperature = 100°C

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Molar mass = ?

Solution:

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PV = nRT

n = PV/RT

n = 0.99 atm × 0.0213 L / 0.0821 atm. L. mol⁻¹. k⁻¹ × 373 K

n =0.02 mol/ 30.6

n = 6.5 × 10⁻⁴ mol

Molar mass = Mass/ number of moles

Molar mass = 0.582 g / 6.5 × 10⁻⁴ mol

Molar mass = 0.09 × 10⁴ g/mol

6 0
3 years ago
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Answer:

Here's what I get  

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