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3 years ago

The chemical formula for sodium sulfate is Na2SO4. How many sulfur atoms are in the formula for sodium sulfate?

Chemistry

2 answers:

Gemiola [76]3 years ago

5 0

Answer:

Explanation:

there is only one sulphur (S) atoms in the formula for sodium sulphate

USPshnik [31]3 years ago

5 0

Answer:

Hello, I hope this helps!

Explanation:

In one molecule of sodium sulfate, or Na2 SO4, there are seven atoms in all.

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Water will melt faster on a very cold soft drink can than it will on a cool soft drink is this physical or chemical change?

Margarita [4]

I believe its chemical change

hope this helps

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3 years ago

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Phosphorus trichloride gas and chlorine gas react to form phosphorus pentachloride gas: PCl3(g)+Cl2(g)⇌PCl5(g). A 7.5-L gas vess

Tpy6a [65]

Answer:

The equilibrium constant in terms of concentration that is, $K_c=3.6243\times 10^{3}$ .

Explanation:

$PCl_3(g)+Cl_2(g)\rightleftharpoons PCl_5(g)$

The relation of $K_c\& K_p$ is given by:

$K_p=K_c(RT)^{\Delta n_g}$

$K_p$ = Equilibrium constant in terms of partial pressure.=98.1

$K_c$ = Equilibrium constant in terms of concentration =?

T = temperature at which the equilibrium reaction is taking place.

R = universal gas constant

$\Delta n_g$ = Difference between gaseous moles on product side and reactant side= $n_{g,p}-n_{g.r}=1-2=-1$

$98.1=K_c(RT)^{-1}$

$98.1 =\frac{K_c}{RT}$

$K_c=98.1\times 0.0821 L atm/mol K\times 450 K=3,624.30=3.6243\times 10^{3}$

The equilibrium constant in terms of concentration that is, $K_c=3.6243\times 10^{3}$ .

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3 years ago

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Find the density.... Mass is 138g and Volume is 100 mL

solniwko [45]

Answer:

1380 kilogram/cubic meter

$p=\frac{m}{v}$

$=\frac{138g}{100mL}$

$=1.38$

$=1380$

4 0

3 years ago

Is sugar ( in water) an example of an element or compound

tresset_1 [31]

Answer:

A compound

Example:

Sugar contains carbon, hydrogen and oxygen. Water (H2O) has two hydrogen atoms (H2) and one oxygen atom (O). So both sugar and water are chemical compounds. Together they are a mix of chemical compounds.

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3 years ago

What is the redox half equation for 3Ag2S + 2Al --> 6Ag + Al2, and identity which material is oxidized and which is reduced?

marta [7]

Answer:

Al is oxidized while Ag is reduced.

Explanation:

The complete molecular equation is;

3Ag2S + 2Al --> 6Ag + Al2S3

Oxidation half equation;

2Al ------> 2Al^3+ + 6e

Reduction half equation;

6Ag^+ + 6e -------> 6Ag

Overall redox reaction equation;

2Al + 6Ag^+ ----->2Al^3+ + 6Ag

Hence; Al is oxidized while Ag is reduced.

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3 years ago